我需要一个用Python制作出来的扫雷游戏，不要有报错的代码

当然，我可以帮你创建一个用Python编写的扫雷游戏。以下是一个基本的实现示例：

import random

def create_board(rows, cols, num_mines):
    board = [[' ' for _ in range(cols)] for _ in range(rows)]
    mines = []
    while len(mines) < num_mines:
        mine = (random.randint(0, rows-1), random.randint(0, cols-1))
        if mine not in mines:
            mines.append(mine)
            board[mine[0]][mine[1]] = 'X'
    return board

def count_adjacent_mines(board, row, col):
    count = 0
    for i in range(max(0, row-1), min(row+2, len(board))):
        for j in range(max(0, col-1), min(col+2, len(board[0]))):
            if board[i][j] == 'X':
                count += 1
    return count

def reveal_cell(board, row, col):
    if board[row][col] != ' ':
        return
    num_mines = count_adjacent_mines(board, row, col)
    board[row][col] = str(num_mines) if num_mines > 0 else ' '
    if board[row][col] == ' ':
        for i in range(max(0, row-1), min(row+2, len(board))):
            for j in range(max(0, col-1), min(col+2, len(board[0]))):
                if i != row or j != col:
                    reveal_cell(board, i, j)

def print_board(board):
    for row in board:
        print(' '.join(row))

def play_game(rows, cols, num_mines):
    board = create_board(rows, cols, num_mines)
    game_over = False
    while not game_over:
        print_board(board)
        row = int(input("Enter row: "))
        col = int(input("Enter col: "))
        if (row < 0 or row >= rows) or (col < 0 or col >= cols):
            print("Invalid cell!")
            continue
        if board[row][col] == 'X':
            print("Game over! You hit a mine.")
            game_over = True
        else:
            reveal_cell(board, row, col)
            if all(all(cell != ' ' for cell in row) for row in board):
                print("Congratulations! You won!")
                game_over = True

# 游戏设置
rows = 8
cols = 8
num_mines = 10

play_game(rows, cols, num_mines)

这是一个简单的扫雷游戏实现示例，你可以根据自己的需要进行修改和扩展。请确保在运行代码之前已经安装了Python。