fixBugIniOS() { const $subMenu = this.$refs.subMenu if ($subMenu) { const handleMouseleave = $subMenu.handleMouseleave $subMenu.handleMouseleave = (e) => { if (this.device === 'mobile') { return } handleMouseleave(e) } } } 这个方法是什么意思

这是一个 JavaScript 方法，可能是在一个 Vue.js 组件中定义的。

该方法的主要作用是修复一个 iOS 设备上的 bug。在这个方法中，首先使用 this.$refs 获取一个名为 subMenu 的组件引用，然后检查该引用是否存在。如果存在，则获取 subMenu 组件的 handleMouseleave 方法，并将其覆盖为一个新的方法。

新的方法通过检查 this.device 是否为 'mobile' 来决定是否执行原来的 handleMouseleave 方法。如果 this.device 为 'mobile'，则不执行原来的方法，否则调用原来的 handleMouseleave 方法。

总的来说，这个方法的目的是为了修复在 iOS 设备上可能出现的一个问题，并确保 subMenu 组件的 handleMouseleave 方法在不同设备上都能正常工作。

相关问题

优化此代码 const openKeys = ref<string[]>([]) const selectedKeys = ref<string[]>([]) const { currentMenu, currentMenuTree, currentMenuList } = storeToRefs( useLayoutStore(), ) const rootSubmenuKeys = currentMenuList.value.filter((v: any) => { if (v.type === 0) { return v.parentId } }) watch( () => currentMenu, () => { openKeys.value = [currentMenu.value?.parentId] selectedKeys.value = [currentMenu.value?.id] }, { immediate: true }, ) const router = useRouter() /** * 点击事件 * @param e 事件对象 */ const handleClick = (e: any) => { const item = currentMenuList.value.find((_) => _.id === e.key) if (item) { router.push(item.path) } } /** * SubMenu 展开/关闭的回调 * @param e 展开的openKeys */ const onOpenChange = (e: any) => { const latestOpenKey = e.find((key: any) => openKeys.value.indexOf(key) === -1) if (rootSubmenuKeys.indexOf(latestOpenKey) === -1) { openKeys.value = e } else { openKeys.value = latestOpenKey ? [latestOpenKey] : [] } }

There are a few optimizations that could be made to this code:

1. Instead of using `ref` for `openKeys` and `selectedKeys`, you can use `reactive` to make the code more concise:

   const state = reactive({
     openKeys: [],
     selectedKeys: [],
   })

2. Instead of using `storeToRefs` to convert the store state to refs, you can use the `toRefs` function, which is shorter and more concise:

   const { currentMenu, currentMenuTree, currentMenuList } = toRefs(useLayoutStore())

3. Instead of using `watch` to watch the `currentMenu` state changes, you can use a computed property to update the `openKeys` and `selectedKeys` arrays:

   const selectedMenu = computed(() => {
     const item = currentMenuList.value.find((_) => _.id === currentMenu.value?.id)
     return [item?.id] || []
   })

   const parentMenu = computed(() => {
     const item = currentMenuList.value.find((_) => _.id === currentMenu.value?.parentId)
     return [item?.id] || []
   })

   watch([selectedMenu, parentMenu], ([selected, parent]) => {
     state.selectedKeys = selected
     state.openKeys = parent
   })

4. Instead of using `router.push` in the `handleClick` function, you can use the `router.push` method directly in the template:

   <Menu.Item :key="item.id" :to="item.path">{{ item.name }}</Menu.Item>

5. Finally, instead of using `rootSubmenuKeys` to filter the list of menu items, you can use a computed property to filter the list of menu items based on their type:

   const subMenuItems = computed(() => {
     return currentMenuList.value.filter((v: any) => v.type === 0 && v.parentId)
   })

By applying these optimizations, the code can be simplified and made more concise.

el-submenu手动展开

可以使用以下代码手动展开`el-submenu`组件：

// 获取需要展开的el-submenu组件
const submenu = this.$refs.submenu;

// 调用组件的展开方法
submenu.handleClick();

其中，`this.$refs.submenu`获取的是`el-submenu`组件的引用，可以在模板中使用`ref`属性来指定。需要注意的是，如果`el-submenu`组件的`mode`属性设置为`horizontal`，则无法手动展开。