写一个代码实现下面要求首先,你需要定义一个数据结构来存储每个亿万富翁的信息,例如姓名、出发城市、到达城市、出发日期、到达日期、财富等等。 然后,你需要按照输入顺序读取每个亿万富翁的信息,并将其存储在上述数据结构中。 接下来,你需要读取旅行列表,并根据旅行列表更新每个亿万富翁的信息,例如更新出发城市、到达城市、出发日期、到达日期、财富等等。 然后,你需要将所有亿万富翁按照到达日期排序,并计算每个城市每天的财富总和。可以使用一个哈希表来存储每个城市每天的财富总和。 最后,你需要遍历哈希表,找到每个城市财富总和最大的天数,并输出城市名称和天数。
时间: 2024-02-18 17:04:09 浏览: 117
好的,我可以给你提供一个伪代码实现的例子,具体实现方式可能会因为数据结构和细节问题略有不同,但整体思路是相似的。
```python
# 定义亿万富翁信息类
class BillionaireInfo:
def __init__(self, name, start_city, end_city, start_date, end_date, wealth):
self.name = name
self.start_city = start_city
self.end_city = end_city
self.start_date = start_date
self.end_date = end_date
self.wealth = wealth
# 存储亿万富翁信息的列表
billionaires = []
# 读取亿万富翁信息
n = int(input())
for i in range(n):
name, start_city, wealth = input().split()
start_date = 1
end_date = 1
billionaires.append(BillionaireInfo(name, start_city, start_city, start_date, end_date, int(wealth)))
# 读取旅行列表并更新亿万富翁信息
m, k = map(int, input().split())
for i in range(k):
day, name, end_city = input().split()
for billionaire in billionaires:
if billionaire.name == name and day > billionaire.end_date:
billionaire.start_city = billionaire.end_city
billionaire.end_city = end_city
billionaire.start_date = billionaire.end_date
billionaire.end_date = int(day)
break
# 按照到达日期排序并计算每个城市每天的财富总和
wealth_by_city_and_day = {}
for billionaire in sorted(billionaires, key=lambda x: x.end_date):
for date in range(billionaire.start_date, billionaire.end_date + 1):
city = billionaire.end_city
if city not in wealth_by_city_and_day:
wealth_by_city_and_day[city] = {}
if date not in wealth_by_city_and_day[city]:
wealth_by_city_and_day[city][date] = 0
wealth_by_city_and_day[city][date] += billionaire.wealth
# 找到每个城市财富总和最大的天数并输出
for city in sorted(wealth_by_city_and_day.keys()):
max_wealth_day = -1
max_wealth = -1
for day, wealth in wealth_by_city_and_day[city].items():
if wealth > max_wealth:
max_wealth = wealth
max_wealth_day = day
if max_wealth_day != -1:
print(city, max_wealth_day)
```
希望这个例子能够帮助你更好地理解整体思路。
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