生成一个包含26对键值对的字典,键是字母的编码数字,值是键对应的字母(A-Z)
时间: 2024-03-12 08:49:07 浏览: 75
好的,下面是生成字母编码字典的 Python 代码:
```
letter_dict = {}
for i in range(65, 91):
letter_dict[i-65] = chr(i)
print(letter_dict)
```
运行结果为:
```
{0: 'A', 1: 'B', 2: 'C', 3: 'D', 4: 'E', 5: 'F', 6: 'G', 7: 'H', 8: 'I', 9: 'J', 10: 'K', 11: 'L', 12: 'M', 13: 'N', 14: 'O', 15: 'P', 16: 'Q', 17: 'R', 18: 'S', 19: 'T', 20: 'U', 21: 'V', 22: 'W', 23: 'X', 24: 'Y', 25: 'Z'}
```
希望能帮到你!
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