用C语言写出离散数学中集合的交集并集补集的程序

下面是用C语言实现集合的交集、并集和补集的程序：

#include <stdio.h>

int main() {
    int set1[100], set2[100], intersection[100], unionSet[200], complement[100], i, j, k, n1, n2, n3 = 0;

    // 输入第一个集合
    printf("Enter number of elements in set1: ");
    scanf("%d", &n1);
    printf("Enter elements of set1: ");
    for (i = 0; i < n1; i++) {
        scanf("%d", &set1[i]);
    }

    // 输入第二个集合
    printf("Enter number of elements in set2: ");
    scanf("%d", &n2);
    printf("Enter elements of set2: ");
    for (i = 0; i < n2; i++) {
        scanf("%d", &set2[i]);
    }

    // 计算交集
    k = 0;
    for (i = 0; i < n1; i++) {
        for (j = 0; j < n2; j++) {
            if (set1[i] == set2[j]) {
                intersection[k++] = set1[i];
                break;
            }
        }
    }
    printf("Intersection of set1 and set2: ");
    for (i = 0; i < k; i++) {
        printf("%d ", intersection[i]);
    }
    printf("\n");

    // 计算并集
    k = 0;
    for (i = 0; i < n1; i++) {
        unionSet[k++] = set1[i];
    }
    for (i = 0; i < n2; i++) {
        for (j = 0; j < n1; j++) {
            if (set2[i] == set1[j]) {
                break;
            }
        }
        if (j == n1) {
            unionSet[k++] = set2[i];
        }
    }
    printf("Union of set1 and set2: ");
    for (i = 0; i < k; i++) {
        printf("%d ", unionSet[i]);
    }
    printf("\n");

    // 计算补集
    k = 0;
    for (i = 0; i < n1; i++) {
        for (j = 0; j < n2; j++) {
            if (set1[i] == set2[j]) {
                break;
            }
        }
        if (j == n2) {
            complement[k++] = set1[i];
        }
    }
    printf("Complement of set1 with respect to set2: ");
    for (i = 0; i < k; i++) {
        printf("%d ", complement[i]);
    }
    printf("\n");

    return 0;
}

程序首先输入两个集合，然后计算它们的交集、并集和补集，并输出结果。