verilog32bit 基2有符号数除法器
时间: 2023-05-16 08:04:37 浏览: 73
这是一个编程类的问题,我可以回答。Verilog 32位基于2的有符号数除法器的代码如下:
module signed_divider(
input signed [31:0] dividend,
input signed [31:0] divisor,
output signed [31:0] quotient,
output signed [31:0] remainder
);
reg signed [31:0] dividend_reg;
reg signed [31:0] divisor_reg;
reg signed [31:0] quotient_reg;
reg signed [31:0] remainder_reg;
reg signed [31:0] divisor_abs;
reg signed [31:0] dividend_abs;
reg signed [31:0] quotient_abs;
reg signed [31:0] remainder_abs;
reg signed [31:0] temp;
always @(*) begin
dividend_reg = dividend;
divisor_reg = divisor;
divisor_abs = divisor_reg < 0 ? -divisor_reg : divisor_reg;
dividend_abs = dividend_reg < 0 ? -dividend_reg : dividend_reg;
quotient_abs = 0;
remainder_abs = dividend_abs;
for (int i = 31; i >= 0; i = i - 1) begin
temp = remainder_abs - (divisor_abs << i);
if (temp >= 0) begin
quotient_abs[i] = 1;
remainder_abs = temp;
end
end
quotient_reg = (dividend_reg < 0) ^ (divisor_reg < 0) ? -quotient_abs : quotient_abs;
remainder_reg = dividend_reg - quotient_reg * divisor_reg;
end
assign quotient = quotient_reg;
assign remainder = remainder_reg;
endmodule
希望这个代码能够帮到你!