编写以下功能函数 （1）求两个数的和 （2）求两个数的差 （3）求两个数的积 （4）求两个数的商

以下是对应功能函数的C代码演示：

1.求两个数的和

#include <stdio.h>

void sum_dif(int n1, int n2, int *sum) {
    *sum = n1 + n2;
}

int main(void) {
    int na, nb, sum = 0;
    printf("请输入两个值：");
    scanf("%d%d", &na, &nb);
    printf("na=%d,nb=%d\n", na, nb);
    sum_dif(na, nb, &sum);
    printf("sum=%d\n", sum);
    return 0;
}

2.求两个数的差

#include <stdio.h>

void sum_dif(int n1, int n2, int *dif) {
    *dif = n1 - n2;
}

int main(void) {
    int na, nb, dif = 0;
    printf("请输入两个值：");
    scanf("%d%d", &na, &nb);
    printf("na=%d,nb=%d\n", na, nb);
    sum_dif(na, nb, &dif);
    printf("dif=%d\n", dif);
    return 0;
}

3.求两个数的积

#include <stdio.h>

void product(int n1, int n2, int *pro) {
    *pro = n1 * n2;
}

int main(void) {
    int na, nb, pro = 0;
    printf("请输入两个值：");
    scanf("%d%d", &na, &nb);
    printf("na=%d,nb=%d\n", na, nb);
    product(na, nb, &pro);
    printf("product=%d\n", pro);
    return 0;
}

4.求两个数的商

#include <stdio.h>

void division(int n1, int n2, float *div) {
    *div = (float)n1 / n2;
}

int main(void) {
    int na, nb;
    float div = 0.0;
    printf("请输入两个值：");
    scanf("%d%d", &na, &nb);
    printf("na=%d,nb=%d\n", na, nb);
    division(na, nb, &div);
    printf("division=%f\n", div);
    return 0;
}