the following code causes java to throw:int number = Integer.MAX_VALUE + 1;

The reason why Java throws an exception when executing the code `int number = Integer.MAX_VALUE + 1` is because the result of the expression `Integer.MAX_VALUE + 1` is greater than the maximum value that can be represented by an integer data type in Java.

The maximum value that can be represented by an integer data type in Java is `2147483647`. When you add 1 to this value, the result is `2147483648` which is greater than the maximum value an int data type can hold. This causes an integer overflow and Java throws an exception.

To fix this issue, you can either use a long data type or handle the overflow exception using try-catch block. For example, you can modify the code as follows:

long number = Integer.MAX_VALUE + 1L;

or

int number;
try {
    number = Math.addExact(Integer.MAX_VALUE, 1);
} catch (ArithmeticException e) {
    // handle the exception
}