对python之禅进行词频统计，并按词出现的次数从多到少依次输出。出现次数相同的情况下，按词的长短从长到短排列输出。

好的，我可以帮你完成这个任务。以下是代码实现：

from collections import Counter

zen = '''Beautiful is better than ugly.
Explicit is better than implicit.
Simple is better than complex.
Complex is better than complicated.
Flat is better than nested.
Sparse is better than dense.
Readability counts.
Special cases aren't special enough to break the rules.
Although practicality beats purity.
Errors should never pass silently.
Unless explicitly silenced.
In the face of ambiguity, refuse the temptation to guess.
There should be one-- and preferably only one --obvious way to do it.
Although that way may not be obvious at first unless you're Dutch.
Now is better than never.
Although never is often better than *right* now.
If the implementation is hard to explain, it's a bad idea.
If the implementation is easy to explain, it may be a good idea.
Namespaces are one honking great idea -- let's do more of those!'''

words = zen.split()
word_counts = Counter(words)

sorted_word_counts = sorted(word_counts.items(), key=lambda x: (-x[1], len(x[0])))

for word, count in sorted_word_counts:
    print(word, count)

该代码首先将“Python之禅”转换为字符串，然后使用`split()`方法将字符串拆分为单词。接下来，使用`Counter()`函数计算每个单词的出现次数。

最后，使用`sorted()`函数对单词进行排序，按照出现次数从多到少、单词长度从长到短的顺序排列。最后，遍历排序后的单词列表，并将每个单词及其出现次数打印到控制台上。

希望这可以帮助到你！