python实现cohen-sutherland裁剪
时间: 2023-07-07 10:20:18 浏览: 85
Cohen-Sutherland裁剪算法是一种基于二维直线段裁剪的算法,下面是Python实现的代码:
```python
# 定义区域码
INSIDE = 0 # 0000
LEFT = 1 # 0001
RIGHT = 2 # 0010
BOTTOM = 4 # 0100
TOP = 8 # 1000
# 计算区域码
def computeCode(x, y, xmin, ymin, xmax, ymax):
code = INSIDE
if x < xmin: # left of rectangle
code |= LEFT
elif x > xmax: # right of rectangle
code |= RIGHT
if y < ymin: # below rectangle
code |= BOTTOM
elif y > ymax: # above rectangle
code |= TOP
return code
# Cohen-Sutherland裁剪算法
def cohenSutherlandClip(x1, y1, x2, y2, xmin, ymin, xmax, ymax):
# 计算起点和终点的区域码
code1 = computeCode(x1, y1, xmin, ymin, xmax, ymax)
code2 = computeCode(x2, y2, xmin, ymin, xmax, ymax)
accept = False
while True:
if code1 == 0 and code2 == 0: # 完全在裁剪区域内
accept = True
break
elif code1 & code2 != 0: # 完全在裁剪区域外
break
else:
x, y = 0, 0
codeOut = code1 if code1 != 0 else code2
if codeOut & TOP: # 线段与裁剪区域的上边界相交
x = x1 + (x2 - x1) * (ymax - y1) / (y2 - y1)
y = ymax
elif codeOut & BOTTOM: # 线段与裁剪区域的下边界相交
x = x1 + (x2 - x1) * (ymin - y1) / (y2 - y1)
y = ymin
elif codeOut & RIGHT: # 线段与裁剪区域的右边界相交
y = y1 + (y2 - y1) * (xmax - x1) / (x2 - x1)
x = xmax
elif codeOut & LEFT: # 线段与裁剪区域的左边界相交
y = y1 + (y2 - y1) * (xmin - x1) / (x2 - x1)
x = xmin
if codeOut == code1: # 更新起点
x1, y1 = x, y
code1 = computeCode(x1, y1, xmin, ymin, xmax, ymax)
else: # 更新终点
x2, y2 = x, y
code2 = computeCode(x2, y2, xmin, ymin, xmax, ymax)
if accept:
return x1, y1, x2, y2
else:
return None
```
以上代码中,`computeCode`函数用于计算点的区域码,`cohenSutherlandClip`函数用于执行裁剪操作。其中,`(x1, y1)`和`(x2, y2)`是线段的起点和终点,`(xmin, ymin)`和`(xmax, ymax)`是裁剪区域的左下角和右上角坐标。函数返回裁剪后的线段端点坐标,如果裁剪区域和线段不相交,返回`None`。
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