完整的能运行的Java代码
时间: 2024-10-10 10:10:16 浏览: 26
Java直接运行JS代码
由于完整的Java代码需要较长篇幅,这里给出一个简化版的例子,展示了如何基本实现这个需求。首先,我们需要导入必要的Java标准库,用于处理IO、解析运算符和计算表达式的功能。下面是一个基础的框架:
```java
import java.io.*;
import java.util.Random;
import java.util.Scanner;
public class ExpressionGenerator {
public static void main(String[] args) {
// 生成随机题目并写入文件
String[] operators = {"+", "-", "max", "min", "doubleMe"};
try (BufferedWriter writer = new BufferedWriter(new FileWriter("question.txt"))) {
int numQuestions = askForNumOfQuestions();
for (int i = 0; i < numQuestions; i++) {
double num1 = getRandomNumber();
double num2 = getRandomNumber();
String operator = operators[new Random().nextInt(operators.length)];
String expression = String.format("%s(%f,%f)", operator, num1, num2);
writer.write(expression + "\n");
}
writer.close();
} catch (IOException e) {
System.out.println("Error writing to file.");
}
// 读取文件并计算结果写入answer.txt
try (BufferedReader reader = new BufferedReader(new FileReader("question.txt"))) {
BufferedWriter answerWriter = new BufferedWriter(new FileWriter("answer.txt"));
String line;
while ((line = reader.readLine()) != null) {
String[] parts = line.split("\\("); // 解析表达式
String op = parts[0].substring(0, parts[0].length() - 1); // 获取运算符
double num1 = Double.parseDouble(parts[1]);
double num2 = Double.parseDouble(parts[2]);
switch (op) {
case "+":
double result = num1 + num2;
break;
// 其他运算符类似...
default:
throw new IllegalArgumentException("Unsupported operator: " + op);
}
answerWriter.write(line + "={" + result + "}\n"); // 添加答案
}
answerWriter.close();
} catch (IOException | NumberFormatException e) {
System.out.println("Error processing expressions.");
}
}
private static double getRandomNumber() {
return Math.random() * 10; // 示例中的简单随机数范围
}
private static int askForNumOfQuestions() {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the number of questions: ");
int num = scanner.nextInt();
return num;
}
}
```
这个例子只处理了加法和乘法,其他运算需要类似地添加。注意这只是一个简化的版本,实际项目中可能会使用正则表达式或者解析库(如JEP)来更精确地解析表达式。此外,对于用户输入的错误检查和异常处理应该也根据实际需求进行完善。
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