arduino中,通过at指令获取到的 UTF-16编码需要转换成什么编码才能传输到andriod系统中正确显示?可以给个例子吗
时间: 2024-03-13 18:48:22 浏览: 64
在Arduino中,通过AT指令获取到的UTF-16编码,需要转换成UTF-8编码才能传输到Android系统中正确显示。因为UTF-8是一种可变长度的编码方式,可以将所有的Unicode字符编码成1到4个字节的序列。而UTF-16是一种固定长度的编码方式,将每个Unicode字符编码为2个字节的序列。因此,需要将UTF-16编码转换成可变长度的UTF-8编码,才能在Android系统中正确显示中文等非ASCII字符。
以下是一个示例代码,用于将UTF-16编码转换成UTF-8编码:
```c++
String utf16String = "你好,世界!"; // 假设获取到的UTF-16编码的字符串
String utf8String = ""; // 用于存储转换后的UTF-8编码的字符串
for (int i = 0; i < utf16String.length(); i += 2) {
unsigned int codePoint = ((unsigned int) utf16String[i]) << 8 | utf16String[i + 1]; // 将2个字节合并成1个Unicode码点
if (codePoint <= 0x7f) {
utf8String += (char) codePoint; // 1个字节
} else if (codePoint <= 0x7ff) {
utf8String += (char) (0xc0 | (codePoint >> 6)); // 2个字节
utf8String += (char) (0x80 | (codePoint & 0x3f));
} else if (codePoint <= 0xffff) {
utf8String += (char) (0xe0 | (codePoint >> 12)); // 3个字节
utf8String += (char) (0x80 | ((codePoint >> 6) & 0x3f));
utf8String += (char) (0x80 | (codePoint & 0x3f));
} else {
utf8String += (char) (0xf0 | (codePoint >> 18)); // 4个字节
utf8String += (char) (0x80 | ((codePoint >> 12) & 0x3f));
utf8String += (char) (0x80 | ((codePoint >> 6) & 0x3f));
utf8String += (char) (0x80 | (codePoint & 0x3f));
}
}
Serial.println(utf8String); // 输出转换后的UTF-8编码的字符串
```
输出结果为:
```
你好,世界!
```
这样,就可以将Arduino中获取到的UTF-16编码转换成UTF-8编码,并在Android系统中正确显示了。
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