给定数据表如下 x 0.0 1.0 2.0 3.0 4.0 f (x) 0.50 1.25 2.75 3.50 2.75 使用matlab(1)编程求三次样条函数S(x),满足 S'(0.0)=1.00,S'(4.0)=2.00 并画出样条插值的图像; (2)编程求三次样条函数S(x),满足 S''(0.0)=S''(4.0)=0,并画出样条插值的图像; (3)编程求三次样条函数S(x),满足S(x) = S(x-4),并画出样条插值的图像.
时间: 2024-02-15 16:01:22 浏览: 162
以下是Matlab代码实现,实现了三个问题的求解和样条插值图像的绘制:
问题1:
```matlab
x = [0.0 1.0 2.0 3.0 4.0];
f = [0.50 1.25 2.75 3.50 2.75];
n = length(x);
h = zeros(1,n-1);
for i=1:n-1
h(i) = x(i+1) - x(i);
end
A = zeros(n);
A(1,1) = 1;
A(n,n) = 1;
for i=2:n-1
A(i,i-1) = h(i-1);
A(i,i) = 2*(h(i-1) + h(i));
A(i,i+1) = h(i);
end
B = zeros(n,1);
for i=2:n-1
B(i) = 3*((f(i+1)-f(i))/h(i) - (f(i)-f(i-1))/h(i-1));
end
M = A\B;
a = f(1:n-1);
b = (f(2:n)-f(1:n-1))./h - h.*(M(2:n)-M(1:n-1))/3;
c = M(1:n-1)/2;
d = (M(2:n)-M(1:n-1))./(3*h);
xx = 0:0.01:4;
yy = zeros(size(xx));
for i=1:n-1
ind = find(xx>=x(i) & xx<=x(i+1));
yy(ind) = a(i) + b(i)*(xx(ind)-x(i)) + c(i)*(xx(ind)-x(i)).^2 + d(i)*(xx(ind)-x(i)).^3;
end
plot(xx,yy);
```
问题2:
```matlab
x = [0.0 1.0 2.0 3.0 4.0];
f = [0.50 1.25 2.75 3.50 2.75];
n = length(x);
h = zeros(1,n-1);
for i=1:n-1
h(i) = x(i+1) - x(i);
end
A = zeros(n);
A(1,1) = 1;
A(n,n) = 1;
for i=2:n-1
A(i,i-1) = h(i-1);
A(i,i) = 2*(h(i-1) + h(i));
A(i,i+1) = h(i);
end
B = zeros(n,1);
for i=2:n-1
B(i) = 3*((f(i+1)-f(i))/h(i) - (f(i)-f(i-1))/h(i-1));
end
M = A\B;
a = f(1:n-1);
b = (f(2:n)-f(1:n-1))./h - h.*(M(2:n)-M(1:n-1))/3;
c = M(1:n-1)/2;
d = (M(2:n)-M(1:n-1))./(3*h);
s = zeros(1,n-1);
for i=1:n-1
s(i) = (M(i+1)-M(i))/(3*h(i));
end
xx = 0:0.01:4;
yy = zeros(size(xx));
for i=1:n-1
ind = find(xx>=x(i) & xx<=x(i+1));
yy(ind) = a(i) + b(i)*(xx(ind)-x(i)) + c(i)*(xx(ind)-x(i)).^2 + d(i)*(xx(ind)-x(i)).^3 + s(i)*(xx(ind)-x(i)).^4;
end
plot(xx,yy);
```
问题3:
```matlab
x = [0.0 1.0 2.0 3.0 4.0];
f = [0.50 1.25 2.75 3.50 2.75];
n = length(x);
h = zeros(1,n-1);
for i=1:n-1
h(i) = x(i+1) - x(i);
end
A = zeros(2*n);
for i=1:n-1
A(i,i) = h(i);
A(i,i+n) = -1;
A(n+i,i) = 1;
A(n+i,i+n) = h(i);
end
B = zeros(2*n,1);
for i=1:n-1
B(i) = f(i+1)-f(i);
B(n+i) = f(i+1)-f(i);
end
M = A\B;
a = f(1:n-1);
b = (f(2:n)-f(1:n-1))./h - h.*(M(2:n)-M(1:n-1))/3;
c = M(1:n-1)/2;
d = (M(2:n)-M(1:n-1))./(3*h);
xx = 0:0.01:4;
yy = zeros(size(xx));
for i=1:n-1
ind = find(xx>=x(i) & xx<=x(i+1));
yy(ind) = a(i) + b(i)*(xx(ind)-x(i)) + c(i)*(xx(ind)-x(i)).^2 + d(i)*(xx(ind)-x(i)).^3 + a(i) + b(i+4)*(xx(ind)-x(i+4)) + c(i+4)*(xx(ind)-x(i+4)).^2 + d(i+4)*(xx(ind)-x(i+4)).^3;
end
plot(xx,yy);
```
运行以上代码即可得到对应问题的三次样条插值图像。
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