int(name[1:])

This code snippet is invalid as it is incomplete. However, assuming that "name" is a string variable, and assuming that the missing part of the code is a function call, this code would attempt to convert a substring of "name" starting from the second character (index 1) to an integer value.

For example, if "name" is the string "12345", the code would attempt to convert the substring "2345" to an integer value. This would result in the integer value 2345.

相关问题

[ERROR] Could not execute SQL statement. Reason: org.apache.flink.table.api.ValidationException: Column types of query result and sink for 'default_catalog.default_database.enriched_orders1' do not match. Cause: Incompatible types for sink column 'email' at position 4. Query schema: [order_id: INT NOT NULL, user_id: STRING, product_id: STRING, address_id: STRING, number: INT, oder_time: TIMESTAMP(6), order_status: STRING, user_name: STRING, gender: STRING, telephone: STRING, email: STRING, code: STRING, province: STRING, city: STRING, product_name: STRING, price: STRING, type: STRING, factory: STRING] Sink schema: [user_id: INT, user_name: STRING, gender: STRING, telephone: STRING, email: STRING, address_id: INT, code: STRING, province: STRING, city: STRING, product_id: INT, product_name: STRING, price: STRING, type: STRING, factory: STRING, order_id: INT, number: INT, order_time: TIMESTAMP(6), order_status: STRING]

这是一个错误信息，看起来是数据表的列类型不匹配导致的。具体来说，查询结果的列类型与目标表不一致，其中 'email' 列的类型不兼容。查询结果的列类型包括 [order_id: INT NOT NULL, user_id: STRING, product_id: STRING, address_id: STRING, number: INT, oder_time: TIMESTAMP(6), order_status: STRING, user_name: STRING, gender: STRING, telephone: STRING, email: STRING, code: STRING, province: STRING, city: STRING, product_name: STRING, price: STRING, type: STRING, factory: STRING]，而目标表的列类型包括[user_id: INT, user_name: STRING, gender: STRING, telephone: STRING, email: STRING, address_id: INT, code: STRING, province: STRING, city: STRING, product_id: INT, product_name: STRING, price: STRING, type: STRING, factory: STRING, order_id: INT, number: INT, order_time: TIMESTAMP(6), order_status: STRING]。需要确认这两个表的列类型是否一致，并作出相应的调整。

#include<iostream> #include<string> using namespace std; class Student { public: Student(int n,string nam) { num=n; name=nam; } void display() { cout<<"num:"<<num<<endl; cout<<"name:"<<name<<endl; } protected: int num; string name; }; class Student1:public Student { public: Student1(int n,string name,int a):Student(n,nam) { age=a; } void show() { display(); cout<<"age:"<<age<<endl; } private: int age; }; class Student2:public Student1 { public: Student2(int n,string name,int a,int s):Student1(n,nam,a) { sex=s; } void show_all() { show(); cout<<"score:"<<score<<endl; } private: int score; }; int main() { Student2 stud(10010,"zaiweitao",17,89); stud.show_all(); return 0; }哪里错了？

您在派生类 `Student1` 的构造函数中将 `nam` 作为参数传递，但 `nam` 并没有定义，应该改为 `name`，即：

Student1(int n, string name, int a) : Student(n, name) {
    age = a;
}

同样，在派生类 `Student2` 的构造函数中，应该将参数 `name` 改为 `nam` 或 `name`，并且要在构造函数中初始化 `score`，否则会有编译错误。改正后的代码如下：

class Student1 : public Student {
public:
    Student1(int n, string name, int a) : Student(n, name) {
        age = a;
    }
    void show() {
        display();
        cout << "age:" << age << endl;
    }
private:
    int age;
};

class Student2 : public Student1 {
public:
    Student2(int n, string name, int a, int s) : Student1(n, name, a) {
        score = s;
    }
    void show_all() {
        show();
        cout << "score:" << score << endl;
    }
private:
    int score;
};

int main() {
    Student2 stud(10010, "zaiweitao", 17, 89);
    stud.show_all();
    return 0;
}

注意：在使用继承时，每个派生类的构造函数必须调用直接基类的构造函数，以确保直接基类的成员得到初始化。