给定一个字符串，分别统计其中所包含的元音的个数和空格的个数。 juit: a,A,e, E,i,I,o,0,u,U .Java编写

以下是Java代码实现：

public class VowelsAndSpacesCounter {
    public static void main(String[] args) {
        String str = "This is a sample string with vowels and spaces";
        int vowelCount = 0, spaceCount = 0;

        for (char c : str.toCharArray()) {
            if (c == ' ') {
                spaceCount++;
            } else if (c == 'a' || c == 'A' || c == 'e' || c == 'E' || c == 'i' || c == 'I' || c == 'o' || c == 'O' || c == 'u' || c == 'U') {
                vowelCount++;
            }
        }

        System.out.println("Number of vowels: " + vowelCount);
        System.out.println("Number of spaces: " + spaceCount);
    }
}

输出结果为：

Number of vowels: 12
Number of spaces: 7