python剪刀石头布用tkinter界面化

好的，下面是一个简单的Python剪刀石头布游戏的Tkinter界面代码：

import tkinter as tk
import random

# 定义游戏规则
rules = {'rock': 'scissors', 'scissors': 'paper', 'paper': 'rock'}

# 定义胜负判断函数
def judge(player_choice, computer_choice):
    if rules[player_choice] == computer_choice:
        return 'You win!'
    elif rules[computer_choice] == player_choice:
        return 'Computer wins!'
    else:
        return 'Tie!'

# 定义按钮点击事件函数
def play(player_choice):
    computer_choice = random.choice(['rock', 'paper', 'scissors'])
    result = judge(player_choice, computer_choice)
    result_label.config(text='You chose: {}\nComputer chose: {}\n{}'.format(player_choice, computer_choice, result))

# 创建窗口
window = tk.Tk()
window.title('Rock Paper Scissors')

# 创建按钮
rock_btn = tk.Button(window, text='Rock', command=lambda: play('rock'))
paper_btn = tk.Button(window, text='Paper', command=lambda: play('paper'))
scissors_btn = tk.Button(window, text='Scissors', command=lambda: play('scissors'))

# 创建结果标签
result_label = tk.Label(window, text='Make your choice!')

# 按钮和结果标签布局
rock_btn.pack(side='left', padx=10, pady=20)
paper_btn.pack(side='left', padx=10, pady=20)
scissors_btn.pack(side='left', padx=10, pady=20)
result_label.pack(pady=20)

# 运行窗口
window.mainloop()

运行代码后，将会弹出一个窗口，上面有三个按钮和一个用于显示结果的标签。玩家点击按钮后，程序会随机出一个电脑的选择，并计算出胜负结果，并在结果标签上显示。