用python写一个尔罗斯方块
时间: 2023-11-29 16:05:44 浏览: 35
当然可以!下面是一个简单的示例,用 Python 编写一个控制台版本的俄罗斯方块游戏:
```python
import random
# 游戏区域的宽度和高度
WIDTH = 10
HEIGHT = 20
# 方块的形状
SHAPES = [
[[1, 1, 1, 1]],
[[1, 1], [1, 1]],
[[1, 0, 0], [1, 1, 1]],
[[0, 0, 1], [1, 1, 1]],
[[0, 1, 1], [1, 1, 0]],
[[1, 1, 0], [0, 1, 1]],
[[0, 1], [1, 1], [0, 1]]
]
# 初始化游戏区域
board = [[0] * WIDTH for _ in range(HEIGHT)]
# 生成一个新的方块
def new_piece():
shape = random.choice(SHAPES)
piece = []
for row in shape:
piece.append(row[:])
return piece
# 在游戏区域中放置方块
def place_piece(board, piece, x, y):
for row in range(len(piece)):
for col in range(len(piece[row])):
if piece[row][col]:
board[y+row][x+col] = 1
# 判断方块是否碰撞到边界或其他方块
def is_collision(board, piece, x, y):
for row in range(len(piece)):
for col in range(len(piece[row])):
if (
piece[row][col] and
(x+col < 0 or x+col >= WIDTH or y+row >= HEIGHT or board[y+row][x+col])
):
return True
return False
# 清除已经填满的行
def clear_rows(board):
full_rows = [row for row in range(HEIGHT) if all(board[row])]
for row in full_rows:
del board[row]
board.insert(0, [0] * WIDTH)
# 打印游戏区域
def print_board(board):
for row in board:
print(' '.join(['#' if cell else '.' for cell in row]))
print()
# 主游戏循环
def main():
piece = new_piece()
x, y = WIDTH // 2 - len(piece[0]) // 2, 0
while True:
# 打印游戏区域
print_board(board)
# 接收用户输入
action = input("Enter 'a' to move left, 'd' to move right, or 'q' to quit: ")
# 移动方块
if action == 'a':
if not is_collision(board, piece, x-1, y):
x -= 1
elif action == 'd':
if not is_collision(board, piece, x+1, y):
x += 1
elif action == 'q':
break
# 下落方块
if not is_collision(board, piece, x, y+1):
y += 1
else:
place_piece(board, piece, x, y)
clear_rows(board)
piece = new_piece()
x, y = WIDTH // 2 - len(piece[0]) // 2, 0
if is_collision(board, piece, x, y):
break
print("Game Over!")
# 运行游戏
if __name__ == '__main__':
main()
```
这个示例使用了二维列表来表示游戏区域,并通过用户输入来控制方块的移动。您可以尝试运行这个代码,并根据需要进行修改和扩展,以创建您自己的俄罗斯方块游戏。希望对您有所帮助!
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