需求：将数组funListT01循环数组 funListT01:[ { id:1, name:'天线1XYZ角度变化情况', data:[ { id:1, time:'2022-10-10 00:00:00', amount:10 }, { id:2, time:'2022-10-11 00:00:00', amount:20 }, { id:2, time:'2022-10-12 00:00:00', amount:20 }, ] }, { id:2, name:'天线2XYZ角度变化情况', data:[ { id:1, time:'2022-10-10 00:00:00', amount:40 }, { id:2, time:'2022-10-11 00:00:00', amount:10 }, { id:2, time:'2022-10-12 00:00:00', amount:60 }, ] }, ], ，组成list数组 list=[ { data:[10, 20, 20, 30, 40, 50, 60, 70], name:"天线1XYZ角度变化情况", stack:"Total", type:"line" }, { data:[40, 10, 60, 90, 120, 30, 200, 20], name:"天线1XYZ角度变化情况", stack:"Total", type:"line" } ]

可以使用循环遍历数组funListT01，然后在每个对象中获取data和name属性，将data属性中的amount值取出来组成一个新的数组，并将name、stack和type属性添加到一个新的对象中，最后将新的对象添加到list数组中即可。以下是示例代码：

let list = [];
for(let item of funListT01) {
  let dataArr = item.data.map(dataItem => dataItem.amount);
  let newObj = {
    data: dataArr,
    name: item.name,
    stack: "Total",
    type: "line"
  };
  list.push(newObj);
}