编写一个使用指针的C函数，交换数组a和数组b的对应元素。 int a[5]={1,2,3,4,5}; int b[5]={10,20,30,40,50}; **输出格式要求："a[%d]=%2d, " "b[%d]=%2d, "

好的，下面是代码实现：

#include <stdio.h>

void swap_array(int *a, int *b, int size) {
    int i;
    for (i = 0; i < size; i++) {
        int temp = a[i];
        a[i] = b[i];
        b[i] = temp;
    }
}

int main() {
    int a[5] = {1, 2, 3, 4, 5};
    int b[5] = {10, 20, 30, 40, 50};
    int size = sizeof(a) / sizeof(int);

    printf("Before swapping:\n");
    for (int i = 0; i < size; i++) {
        printf("a[%d]=%2d, ", i, a[i]);
        printf("b[%d]=%2d\n", i, b[i]);
    }

    swap_array(a, b, size);

    printf("After swapping:\n");
    for (int i = 0; i < size; i++) {
        printf("a[%d]=%2d, ", i, a[i]);
        printf("b[%d]=%2d\n", i, b[i]);
    }

    return 0;
}

输出结果如下：

Before swapping:
a[0]= 1, b[0]=10
a[1]= 2, b[1]=20
a[2]= 3, b[2]=30
a[3]= 4, b[3]=40
a[4]= 5, b[4]=50
After swapping:
a[0]=10, b[0]= 1
a[1]=20, b[1]= 2
a[2]=30, b[2]= 3
a[3]=40, b[3]= 4
a[4]=50, b[4]= 5