帮我优化这段代码 private Map<String, Object> boTOMap(DownloadEpidHfmCaseSevereDeathTableVO tableVO){ this.setSonList(tableVO); List<Map<String, Object>> listMap = CodeToStringUtil.dataObjectProcessing(this.getDataObjectProcessingUtilBO(Arrays.asList(tableVO), true, chinesePattern, kg)); if(CollectionUtils.isNotEmpty(listMap)){ Map<String, Object> objectMap = listMap.get(0); //疫苗 List<EpidHfmCaseSevereDeathTestTableVO> selfTestTableVOS = tableVO.getTestTableVOS().stream().filter(item -> item.getJcdx() == DetectionObjectEnum.SELF).collect(Collectors.toList()); List<EpidHfmCaseSevereDeathTestTableVO> familyMembersTestTableVOS = tableVO.getTestTableVOS().stream().filter(item -> item.getJcdx() == DetectionObjectEnum.FAMILY_MEMBERS).collect(Collectors.toList()); if(CollectionUtils.isNotEmpty(selfTestTableVOS)){ objectMap.put("selfTestTable", this.testTableToMap(selfTestTableVOS)); } if(CollectionUtils.isNotEmpty(familyMembersTestTableVOS)){ objectMap.put("familyMembersTestTable", this.testTableToMap(familyMembersTestTableVOS)); } if(CollectionUtils.isNotEmpty(tableVO.getVaccinateTableVOS())){ objectMap.put("vaccinateTable", this.vaccinateTableToMap(tableVO.getVaccinateTableVOS())); } List<Map<String, Object>> dateList = epidHfmCaseSevereDeathComplicationTableDao.getComplicationTableDateList1(tableVO.getId()); dateList.addAll(epidHfmCaseSevereDeathComplicationTableDao.getComplicationTableDateList2(tableVO.getId(), 7-dateList.size())); if(dateList.size() < 7){ int size = dateList.size(); for (int i = 0; i < (7-size); i++) { Map<String, Object> m = new HashMap<>(); m.put("date", "-"); dateList.add(m); } } objectMap.put("titleList", dateList); if(CollectionUtils.isNotEmpty(tableVO.getComplicationTableVOS())){ List<Map<String, Object>> complicationList = null; Map<ComplicationTypeEnum, List<EpidHfmCaseSevereDeathComplicationTableVO>> listMap1 = tableVO.getComplicationTableVOS().stream().collect(Collectors.groupingBy(EpidHfmCaseSevereDeathComplicationTableVO::getType)); int num = 0; for (int j = 0; j < ComplicationTypeEnum.values().length; j++) { complicationList = new ArrayList<>(); List<Map<String, Object>> bfzmcList = epidHfmCaseSevereDeathComplicationTableDao.getComplicationTableBfzmcList( ComplicationTypeEnum.values()[j], tableVO.getId()); for (Map<String, Object> bfzmc : bfzmcList) { Map<String, Object> complication = new HashMap<>(); complication.put("bfzmc7", bfzmc.get("bfzmc")); for (int i = 0; i < dateList.size(); i++) { num = 0; for (EpidHfmCaseSevereDeathComplicationTableVO complicationTableVO : listMap1.get(ComplicationTypeEnum.values()[j])) { if(complicationTableVO.getDate().equals(dateList.get(i).get("title")) && complicationTableVO.getBfzmc().equals(bfzmc.get("bfzmc"))){ complication.put("bfzmc"+i, StringUtils.isNotBlank(complicationTableVO.getJg()) ? complicationTableVO.getJg() : ""); num = 1; break; } } if(num == 0){ complication.put("bfzmc"+i, ""); } } complicationList.add(complication); } objectMap.put("complicationType"+j, complicationList); } } return objectMap; } return null; }

SpringBoot配置注入实践：String, List, Map与Object类型详解

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Java Map遍历与keySet应用实例

private String listToJSON(Map<String, String> uploadFileMap) 方法中，首先创建一个JSONObject用于存放遍历得到的数据。然后，调用entrySet().iterator()获取Map的键值对集合的迭代器。在while循环中，每次...

解释这段代码@Service("commonService") public class CommonServiceImpl implements CommonService { @Autowired private CommonDao commonDao; @Override public List<String> getOption(Map<String, Object> params) { return commonDao.getOption(params); } @Override public Map<String, Object> getFollowByOption(Map<String, Object> params) { return commonDao.getFollowByOption(params); } @Override public void sh(Map<String, Object> params) { commonDao.sh(params); } @Override public int remindCount(Map<String, Object> params) { return commonDao.remindCount(params); } @Override public Map<String, Object> selectCal(Map<String, Object> params) { return commonDao.selectCal(params); } @Override public List<Map<String, Object>> selectGroup(Map<String, Object> params) { return commonDao.selectGroup(params); } @Override public List<Map<String, Object>> selectValue(Map<String, Object> params) { return commonDao.selectValue(params); }

这些方法的返回值分别是List<String>、Map<String, Object>、void、int、Map<String, Object>、List<Map<String, Object>>和List<Map<String, Object>>。这个类的作用是提供一些通用的数据库访问方法，可以被其他...

封装一个resultMap，映射实体类public class EquipmentVo extends RegionalEquipment { private List<EquipmentDataVo> equipmentDataVoList; private List<Map<String,Object>> maps; public List<Map<String, Object>> getMaps() { return maps; } public void setMaps(List<Map<String, Object>> maps) { this.maps = maps; } public List<EquipmentDataVo> getEquipmentDataVoList() { return equipmentDataVoList; } public void setEquipmentDataVoList(List<EquipmentDataVo> equipmentDataVoList) { this.equipmentDataVoList = equipmentDataVoList; } }，其中map中的键不固定，随着不同的SQL语句而改变，数据源是两个表，存在一对多关系

您可以封装一个resultMap来实现对EquipmentVo实体类的映射，具体实现可以参考以下代码： xml <resultMap id="equipmentVoMap" type="EquipmentVo"> <result property="id" column="id"/> <result property=...

下面的代码,jsonStr长度非常长，java报错常量字符串过长,怎么解决 public static void main(String[] args) { String jsonStr = ""; JSONArray jsonArray = JSON.parseArray(jsonStr); List<Map<String, Object>> list = new ArrayList<>(); for (int i = 0; i < jsonArray.size(); i++) { JSONObject jsonObject = jsonArray.getJSONObject(i); Map<String, Object> map = new HashMap<>(); map.put("id", jsonObject.getString("id")); map.put("name", jsonObject.getString("name")); map.put("parentId", jsonObject.getString("parentId")); list.add(map); } List<Map<String, Object>> treeList = buildTree(list); System.out.println(treeList); } private static List<Map<String, Object>> buildTree(List<Map<String, Object>> list) { List<Map<String, Object>> treeList = new ArrayList<>(); for (Map<String, Object> map : list) { String parentId = (String) map.get("parentId"); if (parentId == null || "".equals(parentId)) { treeList.add(map); } for (Map<String, Object> it : list) { String id = (String) it.get("parentId"); if (map.get("id").equals(id)) { if (map.get("children") == null) { List<Map<String, Object>> children = new ArrayList<>(); children.add(it); map.put("children", children); } else { ((List<Map<String, Object>>) map.get("children")).add(it); } } } } return treeList; }

我看到你的代码中有一个变量名为jsonStr的字符串变量，你说它的长度非常长，导致程序运行时报错。如果你想要解决这个问题，你可以使用以下几种方法之一: 1. 将字符串分割成多个较短的字符串，然后使用 + ...

优化这段代码Map<String, Object> map1 = result.get(0);

这段代码定义了一个名为 map1 的 Map 变量，并从 result 列表中获取第一个元素（即 result.get(0)），将这个元素赋值给 map1。如果想要优化这段代码，可以考虑： 1. 使用 Java 8 的 Stream API，将 for 循环改为 ...

我把我现在的代码给你看下,报错的是:"Parameter 0 of method setTaskletService in com.uniinclusive.jxgfcs.taskletimpl.TaskletContext required a single bean, but 10 were found",代码内容如下: @Component public class TaskletContext<T> { private TaskletService<T> taskletService; @Autowired public void setTaskletService(TaskletService<T> taskletService) { this.taskletService = taskletService; } public List<T> executeTaskletService(List<String> strList, Map<String,Object> map) throws ParseException { return taskletService.match(strList,map); } } @Component public interface TaskletService<T> { List<T> match(List<String> strList, Map<String,Object> map) throws ParseException; } @Component public class ADLoanEntity4Tasklet implements TaskletService<LoanEntity> { @Override public List<LoanEntity> match(List<String> strList, Map<String, Object> map) throws ParseException { List<LoanEntity> list = new ArrayList<>(); return list; } } @Component public class AFFLoanEntity4Tasklet implements TaskletService<LoanEntity> { @Resource private LoanDao loanDao; //字符长度 private final int strLength = 22; @Override public List<LoanEntity> match(List<String> strList, Map<String,Object> map) throws ParseException { List<LoanEntity> list = new ArrayList<>(); return list; } }

根据你提供的代码，出现报错的原因是在 TaskletContext 类的 setTaskletService 方法中存在多个符合条件的 TaskletService<T> bean。为了解决这个问题，你可以尝试以下几种方法： 1. 使用 @Qualifier ...

不是这个意思,我给你看下我的代码: 这是我的泛型接口： @Component public interface TaskletService<T> { List<T> match(List<String> strList, Map<String,Object> map) throws ParseException; } 这是针对接口的策略实现类，有10个，我只列举三个： @Component public class ADLoanEntity4Tasklet implements TaskletService<LoanEntity> { @Override public List<LoanEntity> match(List<String> strList, Map<String, Object> map) throws ParseException { List<LoanEntity> list = new ArrayList<>(); return list; } } @Component public class ABLoanEntity4Tasklet implements TaskletService<LoanEntity> { @Override public List<LoanEntity> match(List<String> strList, Map<String, Object> map) throws ParseException { List<LoanEntity> list = new ArrayList<>(); return list; } } @Component public class ADLoanHisEntity4Tasklet implements TaskletService<LoanHisEntity> { @Override public List<LoanHisEntity> match(List<String> strList, Map<String, Object> map) throws ParseException { List<LoanHisEntity> list = new ArrayList<>(); return list; } } 这是Context类: @Component public class TaskletContext<T> { private TaskletService<T> taskletService; @Autowired public void setTaskletService(TaskletService<T> taskletService) { this.taskletService = taskletService; } public List<T> executeTaskletService(List<String> strList, Map<String,Object> map) throws ParseException { return taskletService.match(strList,map); } } 我现在想在main方法中去调用ADLoanEntity4Tasklet,ABLoanEntity4Tasklet,ADLoanHisEntity4Tasklet去处理不同的业务,请问该如何调用?

List<LoanEntity> loanEntityList = entityContext.executeTaskletService(strList, map); // 调用 ABLoanEntity4Tasklet 处理业务 entityContext.setTaskletService(context.getBean(ABLoanEntity4Tasklet....

rivate static void export(HttpServletResponse response, File file, String fileName, if (response != null) { // 前端导出 try { write(response, book, fileName); } catch (IOException e) { e.printStackTrace(); } } else { // 本地导出 FileOutputStream fos; try { fos = new FileOutputStream(file); ByteArrayOutputStream ops = new ByteArrayOutputStream(); book.write(ops); fos.write(ops.toByteArray()); fos.close(); } catch (Exception e) { e.printStackTrace(); } } Map<String, List>> sheetMap, Map<Integer, List<String>> selectMap) { // 整个 Excel 表格 book 对象 SXSSFWorkbook book = new SXSSFWorkbook(); // 每个 Sheet 页 Set<Entry<String, List>>> entries = sheetMap.entrySet(); for (Entry<String, List>> entry : entries) { List> sheetDataList = entry.getValue(); Sheet sheet = book.createSheet(entry.getKey()); Drawing<?> patriarch = sheet.createDrawingPatriarch();

Map<String, List<List<Object>>> sheetMap, Map<Integer, List<String>> selectMap) { // 整个 Excel 表格 book 对象 SXSSFWorkbook book = new SXSSFWorkbook(); // 每个 Sheet 页 Set<Entry<String, List...

private List<Map<String, Object>> getData() { Map<String, Object>map1 = new HashMap<String, Object>(); map1.put("text", "记账"); map1.put("img", R.drawable.ic_add_default); datalist.add(map1); Map<String, Object>map2 = new HashMap<String, Object>(); map2.put("text", "算账"); map2.put("img", R.drawable.ic_suanpan_default); datalist.add(map2); return datalist; } 详细解释这段代码

这段代码是一个方法 getData()，它返回一个 List<Map<String, Object>> 类型的数据。在个方法中，首先创建了一个空的 datalist 集合，然后向该集合中添加两个 Map 对象。第一个 Map 对象 map1 包含两...

for (Entity e : rsList) { List<String> singleRecord = new ArrayList<>(); nameList.forEach(n -> singleRecord.add(e.get(n) == null ? "" : e.get(n).toString())); if (e.getMetadata().containsKey(ChargeConst.RATE_RULE_DETAIL)) { Set<Map<String, Object>> ruleDtls = (Set<Map<String, Object>>) e.getMetadata().get(ChargeConst.RATE_RULE_DETAIL); Map<Object, Object> mergedMap = ruleDtls.stream() .flatMap(map -> map.entrySet().stream().map(entry -> new AbstractMap.SimpleEntry<>(entry.getKey(), entry.getValue() == null ? "" : entry.getValue()))) .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (oldValue, newValue) -> newValue)); final List<String> finalSingleRecord = singleRecord; valueList.add(IntStream.range(0, finalSingleRecord.size()).mapToObj( i -> finalSingleRecord.get(i).equals("") && mergedMap.get(nameList.get(i)) != null ? mergedMap.get(nameList.get(i)).toString() : finalSingleRecord.get(i)) .collect(Collectors.toList())); continue; } valueList.add(singleRecord); }降低代码复杂度

List<String> singleRecord = new ArrayList<>(); nameList.forEach(n -> singleRecord.add(e.get(n) == null ? "" : e.get(n).toString())); if (e.getMetadata().containsKey(ChargeConst.RATE_RULE_DETAIL)) {...

List<Map<String, Object>> guiJiList 根据guijiMap.get("IN_TIME")时间排序

在Java中，如果你想按照Map<String, Object>中某个键值"IN_TIME"的时间（通常假设是一个可以转换为Comparable类型的值，如Long或Date）对List<Map<String, Object>>进行排序，你可以遍历整个列表，同时使用...

private static void export(HttpServletResponse response, File file, String fileName, Map<String, List>> sheetMap, Map<Integer, List<String>> selectMap) { // 整个 Excel 表格 book 对象 SXSSFWorkbook book = new SXSSFWorkbook(); // 每个 Sheet 页 Set<Entry<String, List>>> entries = sheetMap.entrySet(); for (Entry<String, List>> entry : entries) { List> sheetDataList = entry.getValue(); Sheet sheet = book.createSheet(entry.getKey()); // 创建合并算法数组 int rowLength = sheetDataList.size(); int columnLength = sheetDataList.get(0).size(); int[][] mergeArray = new int[rowLength][columnLength]; for (int i =0 ; i < sheetDataList.size(); i++) { // 每个 Sheet 页中的行数据 Row row = sheet.createRow(i); List<Object> rowList = sheetDataList.get(i); for (int j = 0; j < rowList.size(); j++) { // 每个行数据中的单元格数据 Object o = rowList.get(j); int v = 0; if (o instanceof URL) { // 如果要导出图片的话, 链接需要传递 URL 对象 setCellPicture(book, row, patriarch, i, j, (URL) o); } else { Cell cell = row.createCell(j); if (i == 0) { // 第一行为表头行，采用灰色底背景 v = setCellValue(cell, o, headStyle); } else { // 其他行为数据行，默认白底色 v = setCellValue(cell, o, rowStyle); } } mergeArray[i][j] = v; } } } } 我如何在这里获取档案名称的数据内容并把相同的内容纵向合并起来呢

Map<String, List<Integer>> fileNameRowsMap = new HashMap<>(); for (int i = 0; i < sheetDataList.size(); i++) { // 每个 Sheet 页中的行数据 Row row = sheet.createRow(i); List<Object> rowList = ...

优化代码private List QryAllStaff(SqlSessionTemplate sqlSession, String selectStatement) { Map<String, Object> resultMap = new HashMap<>(); String selectSql = "select * from iuap_apdoc_basedoc.tb_hr_user a where DATE_FORMAT(NOW(), '%Y-%m-%d') = SUBSTRING(a.HR_TIMESTAMP,1,10) "; resultMap.put("sql", selectSql); List<Map<String, Object>> StaffDateList = sqlSession.selectList(selectStatement, resultMap); selectSql = "select * from iuap_apdoc_basedoc.tb_hr_family a where DATE_FORMAT(NOW(), '%Y-%m-%d') = SUBSTRING(a.HR_TIMESTAMP,1,10)"; resultMap.put("sql", selectSql); List<Map<String, Object>> StaffDateList1 = sqlSession.selectList(selectStatement, resultMap); selectSql = "select * from iuap_apdoc_basedoc.tb_hr_education a where DATE_FORMAT(NOW(), '%Y-%m-%d') = SUBSTRING(a.HR_TIMESTAMP,1,10)"; resultMap.put("sql", selectSql); List<Map<String, Object>> StaffDateList2 = sqlSession.selectList(selectStatement, resultMap); selectSql = "select * from iuap_apdoc_basedoc.tb_hr_employment_record a where DATE_FORMAT(NOW(), '%Y-%m-%d') = SUBSTRING(a.HR_TIMESTAMP,1,10)"; resultMap.put("sql", selectSql); List<Map<String, Object>> StaffDateList3 = sqlSession.selectList(selectStatement, resultMap); StaffDateList.addAll(StaffDateList1); StaffDateList.addAll(StaffDateList2); StaffDateList.addAll(StaffDateList3); return StaffDateList; }

private List<Map<String, Object>> QryAllStaff(SqlSessionTemplate sqlSession, String selectStatement) { Map<String, Object> paramMap = Collections.singletonMap("dateStr", LocalDate.now().toString()); ...

List<Map<String, Object>> rowList = jdbcTemplate.queryForList(pageSql);查出来的java.math.BigDecimal字段，怎么赋值给对象的String属性字段

如果你使用的是Spring框架中的jdbcTemplate来执行SQL查询，并且查询结果是一个包含BigDecimal类型的List<Map<String, Object>>，那么在赋值给对象的String属性时，你通常需要进行类型转换。以下是一个简单...

list<map<string,object>> 转 list<实体类>

List<Map<String, Object>> mapList = new ArrayList<>(); // 假设 mapList 中已存在一些 map 元素 List<Entity> entityList = convertToList(mapList); // 调用 convertToList 方法进行转换 // 打印 ...

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