写一段CAD VBA代码,画出平面坐标系中的两条相交线段的角平分线,并将该角平分线旋转45°
时间: 2023-09-03 16:25:32 浏览: 156
### 回答1:
Sub DrawAngleBisector()
Dim pt1 As Variant
Dim pt2 As Variant
Dim pt3 As Variant
Dim pt4 As Variant
Dim pt5 As Variantpt1 = InputBox("请输入第一条线段点1的x坐标")
pt2 = InputBox("请输入第一条线段点1的y坐标")
pt3 = InputBox("请输入第一条线段点2的x坐标")
pt4 = InputBox("请输入第一条线段点2的y坐标")
pt5 = InputBox("请输入第二条线段点1的x坐标")'绘制第一条线段
Dim Line1 As AcadLine
Set Line1 = ThisDrawing.ModelSpace.AddLine(Array(pt1, pt2), Array(pt3, pt4))'绘制第二条线段
Dim Line2 As AcadLine
Set Line2 = ThisDrawing.ModelSpace.AddLine(Array(pt3, pt4), Array(pt5, pt6))'计算线段的中点
Dim ptMid As Variant
ptMid(0) = (pt1 + pt3) / 2
ptMid(1) = (pt2 + pt4) / 2'绘制角平分线
Dim AngleLine As AcadLine
Set AngleLine = ThisDrawing.ModelSpace.AddLine(ptMid, Array(pt5, pt6))'将角平分线移动45°
AngleLine.Rotate ptMid, 45End Sub
### 回答2:
以下是一个用CAD VBA代码绘制相交线段角平分线并将其旋转45°的例子:
在CAD中创建一个新的VBA模块,然后使用以下代码:
Sub DrawBisectorAndRotate()
Dim startPoint1 As Variant
Dim endPoint1 As Variant
Dim startPoint2 As Variant
Dim endPoint2 As Variant
'设置两个相交的线段的起点和终点坐标
startPoint1 = Array(0, 0, 0)
endPoint1 = Array(5, 0, 0)
startPoint2 = Array(2, 2, 0)
endPoint2 = Array(2, -2, 0)
'绘制两条线段
Dim line1 As AcadLine
Dim line2 As AcadLine
Set line1 = ThisDrawing.ModelSpace.AddLine(startPoint1, endPoint1)
Set line2 = ThisDrawing.ModelSpace.AddLine(startPoint2, endPoint2)
'获取相交点坐标
Dim intersectPoint As Variant
intersectPoint = line1.IntersectWith(line2, acExtendNone)
'绘制角平分线
Dim bisectorLine As AcadLine
Set bisectorLine = ThisDrawing.ModelSpace.AddLine(intersectPoint, startPoint1)
'旋转角平分线
Dim rotationAngle As Double
rotationAngle = 45 * (3.14159 / 180) '将角度转换为弧度
bisectorLine.Rotate intersectPoint, rotationAngle
End Sub
确保已经在AUTOCAD中加载了上述VBA代码,然后运行这个宏(方式视AUTOCAD版本而定)。这样,你将在AUTOCAD中获得两条相交线段的角平分线,并将其旋转45°。
### 回答3:
下面是一段基于CAD VBA的代码,用于绘制平面坐标系中两条相交线段的角平分线并将其旋转45°:
Sub DrawAngleBisector()
Dim line1 As AcadLine
Dim line2 As AcadLine
Dim intersectionPoint As Variant
Dim angleBisector1 As AcadLine
Dim angleBisector2 As AcadLine
Dim rotationAngle As Double
Dim rotatedAngleBisector As AcadLine
' 设置两条相交线段的起点和终点坐标
Dim line1StartPoint As Variant
line1StartPoint = Array(0, 0, 0)
Dim line1EndPoint As Variant
line1EndPoint = Array(5, 0, 0)
Dim line2StartPoint As Variant
line2StartPoint = Array(3, 1, 0)
Dim line2EndPoint As Variant
line2EndPoint = Array(3, 5, 0)
' 绘制两条线段
Set line1 = ThisDrawing.ModelSpace.AddLine(line1StartPoint, line1EndPoint)
Set line2 = ThisDrawing.ModelSpace.AddLine(line2StartPoint, line2EndPoint)
' 求两条线段的交点坐标
intersectionPoint = line1.IntersectWith(line2)
' 绘制角平分线
Set angleBisector1 = ThisDrawing.ModelSpace.AddLine(line1.StartPoint, intersectionPoint)
Set angleBisector2 = ThisDrawing.ModelSpace.AddLine(line1.EndPoint, intersectionPoint)
' 计算旋转角度
rotationAngle = 45
' 旋转角平分线
Set rotatedAngleBisector = angleBisector1.CopyRotate(angleBisector1.StartPoint, rotationAngle)
MsgBox "已绘制并旋转成功!"
End Sub
请注意,以上代码是基于AutoCAD VBA进行开发的,所以需要在AutoCAD软件中运行。代码中先定义了两条直线的起点和终点坐标,然后绘制两条线段。接下来使用IntersectWith方法获取两条线段的交点坐标,然后分别绘制两条角平分线。最后通过CopyRotate方法将其中一条角平分线按照指定的旋转角度进行旋转。
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