shell编程实现99乘法表
时间: 2023-04-26 18:03:52 浏览: 89
以下是一个简单的shell脚本,用于打印出99乘法表:
```
#!/bin/bash
for i in {1..9}
do
for j in {1..9}
do
if [ $j -le $i ]
then
echo -n "$j*$i=$(($j*$i)) "
fi
done
echo ""
done
```
运行该脚本,将会输出以下结果:
```
1*1=1
1*2=2 2*2=4
1*3=3 2*3=6 3*3=9
1*4=4 2*4=8 3*4=12 4*4=16
1*5=5 2*5=10 3*5=15 4*5=20 5*5=25
1*6=6 2*6=12 3*6=18 4*6=24 5*6=30 6*6=36
1*7=7 2*7=14 3*7=21 4*7=28 5*7=35 6*7=42 7*7=49
1*8=8 2*8=16 3*8=24 4*8=32 5*8=40 6*8=48 7*8=56 8*8=64
1*9=9 2*9=18 3*9=27 4*9=36 5*9=45 6*9=54 7*9=63 8*9=72 9*9=81
```
相关问题
shell编程九九乘法表
好的,以下是一个简单的shell脚本,用于打印出九九乘法表:
```
#!/bin/bash
for ((i=1;i<=9;i++)); do
for ((j=1;j<=i;j++)); do
echo -n "$j x $i = $((i*j)) " # -n 表示不换行
done
echo "" # 换行
done
```
你可以将这段代码保存为一个文件,比如 `multiplication.sh`,然后在终端中运行。这将打印出九九乘法表。
linuxshell编程99乘法表
以下是Linux Shell编程实现的99乘法表:
```
#!/bin/bash
for i in `seq 1 9`
do
for j in `seq 1 $i`
do
echo -n "$j*$i=$(($j*$i)) "
done
echo ""
done
```
运行结果如下:
```
1*1=1
1*2=2 2*2=4
1*3=3 2*3=6 3*3=9
1*4=4 2*4=8 3*4=12 4*4=16
1*5=5 2*5=10 3*5=15 4*5=20 5*5=25
1*6=6 2*6=12 3*6=18 4*6=24 5*6=30 6*6=36
1*7=7 2*7=14 3*7=21 4*7=28 5*7=35 6*7=42 7*7=49
1*8=8 2*8=16 3*8=24 4*8=32 5*8=40 6*8=48 7*8=56 8*8=64
1*9=9 2*9=18 3*9=27 4*9=36 5*9=45 6*9=54 7*9=63 8*9=72 9*9=81
```
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