qt 怎么用QDataStream读取wav文件最后800个数据并

转化成float类型？

你可以通过以下的代码来实现：

#include <QDataStream>
#include <QFile>

QFile file("audio.wav");
if (!file.open(QIODevice::ReadOnly)) {
    qWarning() << "Failed to open file!";
    return;
}

QDataStream stream(&file);
stream.setByteOrder(QDataStream::LittleEndian); // WAV文件采用小端字节序

// 读取WAV文件头
char riff[4] = {'\0'};
quint32 fileSize = 0;
char wave[4] = {'\0'};
char fmt[4] = {'\0'};
quint32 fmtSize = 0;
quint16 audioFormat = 0;
quint16 numChannels = 0;
quint32 sampleRate = 0;
quint32 byteRate = 0;
quint16 blockAlign = 0;
quint16 bitsPerSample = 0;
while (!stream.atEnd()) {
    stream.readRawData(riff, 4);
    stream >> fileSize;
    stream.readRawData(wave, 4);
    stream.readRawData(fmt, 4);
    stream >> fmtSize;
    stream >> audioFormat;
    stream >> numChannels;
    stream >> sampleRate;
    stream >> byteRate;
    stream >> blockAlign;
    stream >> bitsPerSample;

    if (memcmp(riff, "RIFF", 4) == 0 &&
        memcmp(wave, "WAVE", 4) == 0 &&
        memcmp(fmt, "fmt ", 4) == 0) {
        // 找到WAV文件头
        break;
    }
}

// 跳过不需要的数据块
while (!stream.atEnd()) {
    char data[4] = {'\0'};
    quint32 dataSize = 0;
    stream.readRawData(data, 4);
    stream >> dataSize;

    if (memcmp(data, "data", 4) == 0) {
        // 找到数据块
        break;
    } else {
        stream.skipRawData(dataSize);
    }
}

// 读取最后800个16位的数据，并转换成float类型
const int numSamples = 800;
qint16 data[numSamples] = {0};
for (int i = 0; i < numSamples; i++) {
    stream >> data[i];
}
float floatData[numSamples] = {0};
for (int i = 0; i < numSamples; i++) {
    floatData[i] = static_cast<float>(data[i]) / static_cast<float>(32768);
}

file.close();

上述代码首先打开WAV文件，然后依次读取WAV文件头和数据块，并找到最后800个数据。这里假设WAV文件采用的是16位带符号整数采样，所以读取到的数据需要处理成float类型，范围在[-1.0, 1.0]之间。如果WAV文件采用的是其他的采样格式，需要相应地修改代码。