如何利用这个SQL进行删除出现次数>2的公司,使>2的公司出现次数为1:SELECT company_name, COUNT() AS count FROM ( SELECT company_name, DENSE_RANK() OVER (ORDER BY company_name) AS company_rank FROM your_table_name ) AS subquery GROUP BY company_name HAVING COUNT() > 1;
时间: 2024-03-17 12:46:44 浏览: 45
要将出现次数大于2的公司出现次数变为1,可以使用以下SQL语句:
```
UPDATE your_table_name
SET company_name = 'new_name'
WHERE company_name IN (
SELECT company_name
FROM (
SELECT company_name, COUNT(*) AS count
FROM (
SELECT company_name, DENSE_RANK() OVER (ORDER BY company_name) AS company_rank
FROM your_table_name
) AS subquery
GROUP BY company_name
HAVING COUNT(*) > 2
) AS subquery2
);
DELETE FROM your_table_name
WHERE company_name IN (
SELECT company_name
FROM (
SELECT company_name, COUNT(*) AS count
FROM (
SELECT company_name, DENSE_RANK() OVER (ORDER BY company_name) AS company_rank
FROM your_table_name
) AS subquery
GROUP BY company_name
HAVING COUNT(*) > 2
) AS subquery3
);
```
这个语句会先将表中所有公司按照名称进行排序,并计算它们的排名。然后,将它们分组并计算每个公司出现的次数。接着,将出现次数大于2的公司名称提取出来,并将这些公司的名称更新为一个新的名称,例如'new_name'。最后,将这些公司的所有记录从原表中删除。这样就可以将出现次数大于2的公司出现次数变为1。
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