用数组求fibonacci数列前50项的值
时间: 2023-05-18 21:04:56 浏览: 211
输出fibonacci数列的前40项
好的,以下是用数组求fibonacci数列前50项的值的代码:
```python
fib = [0, 1]
for i in range(2, 51):
fib.append(fib[i-1] + fib[i-2])
print(fib)
```
输出结果为:
```
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, 514229, 832040, 1346269, 2178309, 3524578, 5702887, 9227465, 14930352, 24157817, 39088169, 63245986, 102334155, 165580141, 267914296, 433494437, 701408733, 1134903170, 1836311903, 2971215073, 4807526976, 7778742049, 12586269025]
```
希望这个答案能够帮到你!
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