给出python代码，随机给出50个二维坐标点，使用启发式算法解决包含这50个点的旅行商问题，最终将路线绘制为动画

import random
import matplotlib.pyplot as plt
import matplotlib.animation as animation

# 生成50个随机坐标
coordinates = [(random.randint(0, 100), random.randint(0, 100)) for i in range(50)]

# 使用启发式算法解决旅行商问题
def tsp(coordinates):
visited = [0]
path = []
min_dist = 0
while len(visited) != len(coordinates):
min_dist = float('inf')
for i in range(len(coordinates)):
if i not in visited:
dist = 0
for j in range(len(visited)):
dist += ((coordinates[i][0] - coordinates[visited[j]][0])**2 + (coordinates[i][1] - coordinates[visited[j]][1])**2)**0.5

if dist < min_dist:
min_dist = dist
min_index = i
visited.append(min_index)
path.append(min_index)
return path

# 绘制旅行商路线，并动画播放
def draw_tsp(coordinates, path):
figure = plt.figure()
plt.scatter([x[0] for x in coordinates], [x[1] for x in coordinates], marker = 'x', color = 'blue')
for i in range(len(path)):
if i + 1 == len(path):
plt.plot([coordinates[path[i]][0], coordinates[path[0]][0]], [coordinates[path[i]][1], coordinates[path[0]][1]], color = 'black')
else:
plt.plot([coordinates[path[i]][0], coordinates[path[i + 1]][0]], [coordinates[path[i]][1], coordinates[path[i + 1]][1]], color = 'black')
def animate(i):
line.set_data([], [])
if i + 1 == len(path):
line, = plt.plot([coordinates[path[i]][0], coordinates[path[0]][0]], [coordinates[path[i]][1], coordinates[path[0]][1]], color = 'red')
else:
line, = plt.plot([coordinates[path[i]][0], coordinates[path[i + 1]][0]], [coordinates[path[i]][1], coordinates[path[i + 1]][1]], color = 'red')
return line,
ani = animation.FuncAnimation(figure, animate, frames = len(path), interval = 1000, blit = True)
plt.show()

# 主函数
if __name__ == "__main__":
path = tsp(coordinates)
draw_tsp(coordinates, path) 答案：我可以为您提供Python代码，使用启发式算法来解决包含50个点的旅行商问题，并将路线绘制为动画。