指令编程实现两个128位数相减

可以使用以下代码实现两个128位数的减法：

def subtract(num1, num2):
    # Convert the numbers to binary strings
    bin1 = bin(num1)[2:].zfill(128)
    bin2 = bin(num2)[2:].zfill(128)
    
    # Perform the subtraction
    result = ''
    carry = 0
    for i in range(127, -1, -1):
        diff = int(bin1[i]) - int(bin2[i]) - carry
        if diff < 0:
            diff += 2
            carry = 1
        else:
            carry = 0
        result = str(diff) + result
    
    # Convert the result back to an integer
    return int(result, 2)

这个函数接受两个参数，分别是要相减的两个128位数。它将这两个数转换成二进制字符串，然后从高位到低位逐位相减，处理借位，最后将结果转换回整数并返回。