编程判断输入整数x的正负性和奇偶性。 **输入格式要求:"%d" 提示信息:"Enter a integer:" **输出格式要求:"The integer is a plus even number\n" "This integer is a plus odd number\n" "This integer is a minus even number\n" "This integer is a minus odd number\n" "This integer is zero.\n" 程序运行示例如下: Enter a integer:-9 This integer is a minus odd number
时间: 2023-07-05 13:31:42 浏览: 121
下面是一个示例Python程序,可以实现上述的要求:
```python
x = int(input("Enter a integer:"))
if x > 0:
if x % 2 == 0:
print("The integer is a plus even number")
else:
print("This integer is a plus odd number")
elif x < 0:
if x % 2 == 0:
print("This integer is a minus even number")
else:
print("This integer is a minus odd number")
else:
print("This integer is zero.")
```
该程序通过`input()`函数读取用户输入的整数`x`,然后使用嵌套的`if`语句判断`x`的正负性和奇偶性,并使用`print()`函数输出相应的信息。注意,在判断奇偶性时,可以使用取模运算符`%`来判断一个整数是否为偶数。若`x % 2`的值为0,则`x`为偶数,否则`x`为奇数。
相关问题
C语言编程判断输入整数x的正负性和奇偶性。 **输入格式要求:"%d" 提示信息:"Enter a integer:" **输出格式要求:"The integer is a plus even number\n" "This integer is a plus odd number\n" "This integer is a minus even number\n" "This integer is a minus odd number\n" "This integer is zero.\
以下是 C 语言代码实现:
```c
#include <stdio.h>
int main() {
int x;
printf("Enter an integer: ");
scanf("%d", &x);
if (x > 0) {
if (x % 2 == 0) {
printf("The integer is a plus even number\n");
} else {
printf("This integer is a plus odd number\n");
}
} else if (x < 0) {
if (x % 2 == 0) {
printf("This integer is a minus even number\n");
} else {
printf("This integer is a minus odd number\n");
}
} else {
printf("This integer is zero.\n");
}
return 0;
}
```
代码逻辑比较简单,就是先判断正负性,再判断奇偶性,最后输出相应的结果。其中 `%d` 表示输入的是整数,`scanf` 函数用于输入。输出格式要求依次判断即可。
编程判断输入整数x的正负性和奇偶性。 **输入格式要求:"%d" 提示信息:"Enter a integer:" **输出格式要求:"The integer is a plus even number\n" "This integer is a plus odd number\n" "This integer is a minus even number\n" "This integer is a minus odd number\n" "This integer is zero.\n"
好的,以下是对应的C语言代码:
```c
#include <stdio.h>
int main() {
int x;
printf("Enter a integer:");
scanf("%d", &x);
// 判断正负性和奇偶性
if (x > 0) {
if (x % 2 == 0) {
printf("The integer is a plus even number\n");
} else {
printf("This integer is a plus odd number\n");
}
} else if (x < 0) {
if (x % 2 == 0) {
printf("This integer is a minus even number\n");
} else {
printf("This integer is a minus odd number\n");
}
} else {
printf("This integer is zero.\n");
}
return 0;
}
```
希望能对你有所帮助!
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