matlab中双电梯仿真代码

以下是一个简单的双电梯仿真代码，使用 MATLAB 编写：

% 建立一个包含10个楼层的大厦
num_floors = 10;
building = zeros(num_floors, 1);

% 建立两部电梯
elevator1 = struct('name', 'Elevator 1', 'capacity', 8, 'cur_floor', 1, 'direction', 1, 'passengers', []);
elevator2 = struct('name', 'Elevator 2', 'capacity', 8, 'cur_floor', 1, 'direction', 1, 'passengers', []);

% 处理电梯内乘客的上下车
function [elevator, passengers] = process_passengers(elevator, passengers)
    num_passengers = length(passengers);
    for i = num_passengers:-1:1
        if passengers(i).dest_floor == elevator.cur_floor
            fprintf("Passenger %d gets off %s at floor %d\n", passengers(i).id, elevator.name, elevator.cur_floor);
            passengers(i) = [];
        elseif length(elevator.passengers) < elevator.capacity && passengers(i).dest_floor > elevator.cur_floor == elevator.direction
            fprintf("Passenger %d gets on %s at floor %d\n", passengers(i).id, elevator.name, elevator.cur_floor);
            elevator.passengers = [elevator.passengers; passengers(i)];
            passengers(i) = [];
        end
    end
end

% 模拟电梯运行
function elevator = run_elevator(elevator, passengers, building)
    elevator = elevator;
    % 处理电梯内乘客的上下车
    [elevator, passengers] = process_passengers(elevator, passengers);
    % 判断是否需要改变运行方向
    if elevator.cur_floor == 1
        elevator.direction = 1;
    elseif elevator.cur_floor == num_floors
        elevator.direction = -1;
    elseif any(building(elevator.cur_floor + elevator.direction:end))
        elevator.direction = elevator.direction;
    else
        elevator.direction = -elevator.direction;
    end
    % 移动电梯一层楼
    elevator.cur_floor = elevator.cur_floor + elevator.direction;
end

% 模拟乘客等待电梯
function [passengers, building] = wait_passengers(passengers, building)
    if rand() < 0.1
        floor = randi(num_floors);
        dest_floor = randi(num_floors);
        while dest_floor == floor
            dest_floor = randi(num_floors);
        end
        passenger = struct('id', length(passengers) + 1, 'dest_floor', dest_floor);
        passengers = [passengers; passenger];
        building(floor) = sign(dest_floor - floor);
        fprintf("Passenger %d waits for elevator at floor %d to go %d\n", passenger.id, floor, passenger.dest_floor);
    end
end

% 模拟电梯调度
function [elevator, passengers, building] = dispatch_elevator(elevator, passengers, building)
    for i = 1:num_floors
        if building(i) ~= 0 && elevator.cur_floor == i && length(elevator.passengers) < elevator.capacity
            fprintf("Passenger calls %s at floor %d to go %d\n", elevator.name, i, building(i));
            elevator.direction = building(i);
            building(i) = 0;
            for j = 1:length(passengers)
                if passengers(j).dest_floor == i && passengers(j).dest_floor > elevator.cur_floor == elevator.direction
                    fprintf("Passenger %d gets on %s at floor %d\n", passengers(j).id, elevator.name, elevator.cur_floor);
                    elevator.passengers = [elevator.passengers; passengers(j)];
                    passengers(j) = [];
                end
            end
        end
    end
end

% 初始化乘客
passengers = [];
building = zeros(num_floors, 1);

% 模拟电梯运行和乘客等待
for i = 1:100
    % 模拟电梯运行
    elevator1 = run_elevator(elevator1, passengers, building);
    elevator2 = run_elevator(elevator2, passengers, building);
    % 模拟乘客等待电梯
    [passengers, building] = wait_passengers(passengers, building);
    % 模拟电梯调度
    [elevator1, passengers, building] = dispatch_elevator(elevator1, passengers, building);
    [elevator2, passengers, building] = dispatch_elevator(elevator2, passengers, building);
    % 模拟时间流逝
    pause(1);
end

这个代码中模拟了一个有10层楼的大厦，有两部电梯在运行。乘客在大厦内等待电梯，当电梯到达时乘客会上电梯，然后电梯会根据乘客的目的地运行。同时，电梯也会按照呼叫队列中的需求进行运行。这个代码仅供参考，还有很多地方可以进行优化和改进。