写代码来求出现次数最多的长度为2的子串
时间: 2024-05-04 17:16:42 浏览: 15
好的,我可以帮你解决这个问题。你可以使用一个字典来存储每个长度为2的子串出现的次数,然后找出出现次数最多的子串。下面是Python的示例代码:
```
string = "This is a sample string with repeated substrings"
substrings = {}
# Loop through the string, skipping the last character
for i in range(len(string) - 1):
# Get the current substring of length 2
substring = string[i:i+2]
# If the substring is not yet in the dictionary, add it with a count of 0
if substring not in substrings:
substrings[substring] = 0
# Increment the count for the substring
substrings[substring] += 1
# Find the substring with the highest count
max_substring = max(substrings, key=substrings.get)
print("The most common substring is '{}' with a count of {}".format(max_substring, substrings[max_substring]))
```
请注意,这只是一个简单的示例代码,并且有些复杂性问题并未解决,例如相同计数的子串数量超过一个。如果需要更复杂的解决方案,请告诉我。
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