假设有一个灰度图像，其大小为64 x 64，灰度级为8，利用直方图均衡化方法进行直方图均衡化c++代码

其代码如下：

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

#define WIDTH 64
#define HEIGHT 64
#define DEPTH 8

void histogram_equalization(unsigned char *image, unsigned int width, unsigned int height, unsigned int depth)
{
    // Calculate histogram and corresponding probabilities
    int histogram[DEPTH] = { 0 };
    double prob[DEPTH] = { 0.0 };
    for (unsigned int i = 0; i < width * height; i++)
    {
        histogram[image[i]]++;
    }
    for (unsigned int i = 0; i < DEPTH; i++)
    {
        prob[i] = (double) histogram[i] / ((double) width * (double) height);
    }

    // Calculate cumulative distribution function
    double cdf[DEPTH] = { 0.0 };
    for (unsigned int i = 0; i < DEPTH; i++)
    {
        if (i == 0)
        {
            cdf[i] = prob[i];
        }
        else
        {
            cdf[i] = cdf[i - 1] + prob[i];
        }
    }

    // Convert cdf to histeq table
    unsigned char histeq_table[DEPTH] = { 0 };
    for (unsigned int i = 0; i < DEPTH; i++)
    {
        histeq_table[i] = (unsigned char) round((DEPTH - 1) * cdf[i]);
    }

    // Apply histeq table to image
    for (unsigned int i = 0; i < width * height; i++)
    {
        image[i] = histeq_table[image[i]];
    }
}

int main(void)
{
    // Load image
    unsigned char image[WIDTH * HEIGHT] = { 63, 24, 5, 32, 62, 45, 12, 19, 30, 56, 52, 13, 4, 35, 42, 50, 38, 54, 7, 25, 1, 27, 12, 46, 32, 8, 23, 17, 3, 18, 9, 48, 55, 41, 20, 51, 2, 14, 57, 61, 31, 26, 63, 39, 53, 6, 37, 10, 33, 40, 36, 11, 28, 44, 58, 22, 47, 16, 59, 49, 15, 29, 43, 21, 60 };
    
    // Apply histogram equalization
    histogram_equalization(image, WIDTH, HEIGHT, DEPTH);

    // Print result
    for (unsigned int y = 0; y < HEIGHT; y++)
    {
        for (unsigned int x = 0; x < WIDTH; x++)
        {
            printf("%d ", image[y * WIDTH + x]);
        }
        printf("\n");
    }

    return 0;
}

请注意，这只是一个示例实现，实际上有很多种实现直方图均衡化的方法。