c➕➕求两个变量最大值的函数模版

以下是求两个变量最大值的函数模板，其中使用了 C++ 的模板特性，可以适用于不同类型的变量：

template <typename T>
T max(T a, T b) {
    return (a > b) ? a : b;
}

使用示例：

int a = 10, b = 20;
cout << max(a, b) << endl; // 输出 20

double c = 3.14, d = 2.718;
cout << max(c, d) << endl; // 输出 3.14

相关问题

函数重载实现了让同名函数处理不同类型的数据，但最好的解决方法是类型参数化，这样就得到了函数模板。使用模板的目的就是能够让程序员编写与类型无关的代码。要求设计求两个或三个不同类型变量之最大值的函数模板，并在主函数中进行测试。 函数接口定义： template<class T> T myMax(T a,T b); template<class T> T myMax(T a,T b,T c); T是抽象类型，可以由int,double,char,string类型实例化，两个函数模板也可以进行重载。 裁判测试程

序如下：

#include <iostream>
#include <string>

using namespace std;

template<class T>
T myMax(T a, T b) {
    return (a > b) ? a : b;
}

template<class T>
T myMax(T a, T b, T c) {
    return myMax(myMax(a, b), c);
}

int main() {
    int int1 = 10, int2 = 20, int3 = 30;
    double double1 = 10.5, double2 = 20.5, double3 = 30.5;
    char char1 = 'a', char2 = 'b', char3 = 'c';
    string string1 = "hello", string2 = "world", string3 = "!";
    
    cout << "Max of " << int1 << " and " << int2 << " is " << myMax(int1, int2) << endl;
    cout << "Max of " << int1 << ", " << int2 << ", and " << int3 << " is " << myMax(int1, int2, int3) << endl;
    
    cout << "Max of " << double1 << " and " << double2 << " is " << myMax(double1, double2) << endl;
    cout << "Max of " << double1 << ", " << double2 << ", and " << double3 << " is " << myMax(double1, double2, double3) << endl;
    
    cout << "Max of " << char1 << " and " << char2 << " is " << myMax(char1, char2) << endl;
    cout << "Max of " << char1 << ", " << char2 << ", and " << char3 << " is " << myMax(char1, char2, char3) << endl;
    
    cout << "Max of " << string1 << " and " << string2 << " is " << myMax(string1, string2) << endl;
    cout << "Max of " << string1 << ", " << string2 << ", and " << string3 << " is " << myMax(string1, string2, string3) << endl;

    return 0;
}

输出结果如下：

Max of 10 and 20 is 20
Max of 10, 20, and 30 is 30
Max of 10.5 and 20.5 is 20.5
Max of 10.5, 20.5, and 30.5 is 30.5
Max of a and b is b
Max of a, b, and c is c
Max of hello and world is world
Max of hello, world, and ! is world

C++ 编写求最大值max和最小值min的函数模板，函数参数为求两个数的最值。编写完整程序验证。 要求：多文件结构

好的，以下是 C++ 的求最大值和最小值的函数模板的实现：

在 `max_min.hpp` 中，实现模板函数 `max_min`：

template <typename T>
void max_min(T a, T b, T& max_val, T& min_val) {
    if (a > b) {
        max_val = a;
        min_val = b;
    } else {
        max_val = b;
        min_val = a;
    }
}

在 `main.cpp` 中，编写主函数来验证：

#include <iostream>
#include "max_min.hpp"

int main() {
    int x = 1, y = 2, max_val, min_val;
    max_min(x, y, max_val, min_val);
    std::cout << "x = " << x << ", y = " << y << std::endl;
    std::cout << "max_val = " << max_val << ", min_val = " << min_val << std::endl;

    double a = 1.5, b = 3.7, max_val_d, min_val_d;
    max_min(a, b, max_val_d, min_val_d);
    std::cout << "a = " << a << ", b = " << b << std::endl;
    std::cout << "max_val_d = " << max_val_d << ", min_val_d = " << min_val_d << std::endl;

    return 0;
}

这里定义了两个变量 `x` 和 `y`，以及两个变量 `a` 和 `b`，然后分别调用 `max_min` 函数，输出最大值和最小值。

编译并运行：

g++ main.cpp -o main
./main

输出结果为：

x = 1, y = 2
max_val = 2, min_val = 1
a = 1.5, b = 3.7
max_val_d = 3.7, min_val_d = 1.5

可以看到，函数模板正确地输出了每组输入中的最大值和最小值。