ra1=0; r2=0.018; r1=0.0178; miu0=0.003065; b=0.015; while theta > pi/9 theta = theta-pi/9; end if theta == 0 ra1= 1/(miu0*b/(pi/2)*log(r2/r1)+0.5*miu0/(pi/90)*log(r2/r1)); 将下面这段代码做成循环函数ra1=0; r2=0.018; r1=0.0178; miu0=0.003065; b=0.015; while theta > pi/9 theta = theta-pi/9; end if theta == 0 ra1= 1/(miu0*b/(pi/2)*log(r2/r1)+0.5*miu0/(pi/90)*log(r2/r1)); else if (theta>0)&(theta<=pi/90) ra1 = 1/(2*miu0*b/(pi/2)*log(r2/r1)+miu0/(pi/90-theta)*log(r2/r1)); else if (theta>pi/90)&(theta<=pi/18) ra1 = 1/(miu0*b/log(r2/r1)*(theta-pi/90)); else if (theta>pi/18)&(theta<=pi/10) ra1 = 1/(miu0*b/log(r2/r1)*(2*pi/45+1/18*pi-theta)); else if (theta>pi/10)&(theta<=pi/9) ra1= 1/(2*miu0*b/(pi/2)*log(r2/r1)+miu0/(theta-pi/10)*log(r2/r1)); end end end end end

你的要求是将上述代码转换为循环函数。下面是转换后的代码：

def calculate_ra1(theta):
    ra1 = 0
    r2 = 0.018
    r1 = 0.0178
    miu0 = 0.003065
    b = 0.015

    while theta > pi/9:
        theta = theta - pi/9

    if theta == 0:
        ra1 = 1 / (miu0*b/(pi/2)*log(r2/r1) + 0.5*miu0/(pi/90)*log(r2/r1))
    elif (theta > 0) and (theta <= pi/90):
        ra1 = 1 / (2*miu0*b/(pi/2)*log(r2/r1) + miu0/(pi/90-theta)*log(r2/r1))
    elif (theta > pi/90) and (theta <= pi/18):
        ra1 = 1 / (miu0*b/log(r2/r1)*(theta-pi/90))
    elif (theta > pi/18) and (theta <= pi/10):
        ra1 = 1 / (miu0*b/log(r2/r1)*(2*pi/45+1/18*pi-theta))
    elif (theta > pi/10) and (theta <= pi/9):
        ra1 = 1 / (2*miu0*b/(pi/2)*log(r2/r1) + miu0/(theta-pi/10)*log(r2/r1))

    return ra1

你可以将 `theta` 的值传递给 `calculate_ra1` 函数，它将返回相应的 `ra1` 值。请注意，这只是一个转换，我没有对代码逻辑进行任何更改。