count = 0 while 1: val = yield count if val is not None: print(f"val is {val}") count = val else: count += 1 s1 = send_val() print(next(s1)) print(next(s1)) print(s1.send(0)) print(next(s1))
时间: 2024-04-07 16:29:13 浏览: 13
这段代码定义了一个生成器函数 `send_val()`,它包含一个无限循环 `while 1`,在循环中,通过 `yield` 语句返回计数器 `count`。当调用方使用 `send()` 方法向生成器发送一个值时,该值将被存储在变量 `val` 中,并根据该值更新计数器 `count`。如果发送的值为 `None`,则 `count` 被增加1。如果发送的值不为 `None`,则打印该值,并将 `count` 设置为该值。该程序的输出是:0、1、0、1。
相关问题
int n1 = l1 ? l1->val: 0;
This code initializes an integer variable n1 with the value of l1->val if l1 is not null, otherwise it sets n1 to 0. Here, l1 is presumably a pointer to a node in a linked list, and l1->val is the value stored in that node.
The ternary operator "?" is used to check if l1 is not null. If it is not null, then n1 is set to l1->val, otherwise it is set to 0. This is a shorthand way of writing an if-else statement.
Overall, this code is a simple way to handle null values in a linked list without having to write an if-else statement explicitly.
val=eval(input()) if val<0 val*=-1 print(val)
这段代码的功能是读取用户输入的值,如果其小于0,则将其取绝对值并输出,否则直接输出该值。需要注意的是,这段代码中缺少了一个冒号(:),应该是这样的:
```
val = eval(input())
if val < 0:
val *= -1
print(val)
```
这样才是正确的 Python 代码。