通过ServletConfig接口获取并输出id,name,age
时间: 2023-05-20 13:03:52 浏览: 50
您可以使用以下代码来获取并输出id、name和age:
```java
public void init(ServletConfig config) throws ServletException {
super.init(config);
String id = config.getInitParameter("id");
String name = config.getInitParameter("name");
String age = config.getInitParameter("age");
System.out.println("id: " + id + ", name: " + name + ", age: " + age);
}
```
请注意,这段代码应该放在Servlet的init()方法中。您需要在web.xml文件中配置id、name和age参数,如下所示:
```xml
<servlet>
<servlet-name>MyServlet</servlet-name>
<servlet-class>com.example.MyServlet</servlet-class>
<init-param>
<param-name>id</param-name>
<param-value>123</param-value>
</init-param>
<init-param>
<param-name>name</param-name>
<param-value>John</param-value>
</init-param>
<init-param>
<param-name>age</param-name>
<param-value>30</param-value>
</init-param>
</servlet>
```
这样,当您访问MyServlet时,id、name和age参数将被读取并输出到控制台。