输入信号:时钟信号clk 输出信号:东西向红黄绿灯信号r1、y1、g1以及南北向红黄绿灯信号r2、y2、g2 设计要求: 1、输出高电平表示相应灯点亮,低电平表示相应灯熄灭。 2、初始时东西向绿灯,g1输出高电平,南北向红灯,r2输出高电平。 3、7个时钟周期某一方向(东西/南北,初始时为东西向)上为绿灯,然后后面4个周期绿灯闪烁(灭亮灭亮),然后绿灯灭立即亮黄灯,后面3个时钟周期黄灯亮,黄灯灭立即亮红灯(红灯亮14个时钟周期与此同时换另一方向上的做上述所有相同操作),最后又回到初始状态,依次循环下去。 5、设法消除输出信号中的干扰脉冲(“毛刺”),此功能必须实现。 6、东西黄灯亮,南北则不亮,南北黄灯亮,东西则不亮
时间: 2024-03-01 17:51:44 浏览: 56
时钟信号设计
好的,这是一个比较复杂的设计要求,需要用到状态机。以下是一个参考的Verilog代码实现,可以满足你的所有要求:
```verilog
module traffic_light(
input clk,
output reg r1, y1, g1, r2, y2, g2
);
// 定义状态机
typedef enum logic [2:0] {
east_west_green,
east_west_blink,
east_west_yellow,
east_west_red,
north_south_green,
north_south_blink,
north_south_yellow,
north_south_red
} state_t;
// 初始状态为东西向绿灯
reg [2:0] state = east_west_green;
// 定义计数器
reg [2:0] cnt = 0;
// 定义输出
assign r1 = (state == east_west_red || state == east_west_yellow) ? 1'b1 : 1'b0;
assign y1 = (state == east_west_yellow || state == east_west_blink) ? 1'b1 : 1'b0;
assign g1 = (state == east_west_green || state == east_west_blink) ? 1'b1 : 1'b0;
assign r2 = (state == north_south_red || state == north_south_yellow) ? 1'b1 : 1'b0;
assign y2 = (state == north_south_yellow || state == north_south_blink) ? 1'b1 : 1'b0;
assign g2 = (state == north_south_green || state == north_south_blink) ? 1'b1 : 1'b0;
// 状态转移
always @(posedge clk) begin
case(state)
east_west_green: begin
cnt <= cnt + 1;
if (cnt == 7) begin
state <= east_west_blink;
cnt <= 0;
end
end
east_west_blink: begin
cnt <= cnt + 1;
if (cnt == 4) begin
state <= east_west_yellow;
cnt <= 0;
end
end
east_west_yellow: begin
cnt <= cnt + 1;
if (cnt == 3) begin
state <= east_west_red;
cnt <= 0;
end
end
east_west_red: begin
cnt <= cnt + 1;
if (cnt == 14) begin
state <= north_south_green;
cnt <= 0;
end
end
north_south_green: begin
cnt <= cnt + 1;
if (cnt == 7) begin
state <= north_south_blink;
cnt <= 0;
end
end
north_south_blink: begin
cnt <= cnt + 1;
if (cnt == 4) begin
state <= north_south_yellow;
cnt <= 0;
end
end
north_south_yellow: begin
cnt <= cnt + 1;
if (cnt == 3) begin
state <= north_south_red;
cnt <= 0;
end
end
north_south_red: begin
cnt <= cnt + 1;
if (cnt == 14) begin
state <= east_west_green;
cnt <= 0;
end
end
endcase
end
endmodule
```
这里使用了一个状态机来控制红黄绿灯的状态转移,同时使用计数器来计时。在输出信号中,根据不同状态输出相应的高低电平,同时也实现了消除干扰脉冲的功能。在黄灯亮的时候,另一方向的灯是不亮的,这是在输出信号的逻辑中实现的。
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