帮我写出具体实现过程代码
时间: 2024-03-26 15:40:06 浏览: 55
邮箱代码实现过程详细
好的,以下是一个更为详细的 Python 实现过程代码,包括读取学校信息、计算学校评分、根据评分排序、输出预测结果等过程:
```python
# 读取学校信息
def read_school_info():
# 从文件中读取学校信息
with open('schools.txt', 'r', encoding='utf-8') as f:
lines = f.readlines()
schools = []
for line in lines:
fields = line.strip().split(',')
name = fields[0]
city = fields[1]
low_score = float(fields[2])
plan = int(fields[3])
feature = fields[4]
school = {'name': name, 'city': city, 'low_score': low_score, 'plan': plan, 'feature': feature}
schools.append(school)
return schools
# 计算学校评分
def calculate_score(school, score):
# 计算学校评分,这里使用加权平均分计算
# 其中,录取分数线的权重为 0.6,招生计划的权重为 0.3,特色的权重为 0.1
score_line_weight = 0.6
plan_weight = 0.3
feature_weight = 0.1
score_line_score = (school['low_score'] - score) / school['low_score'] * 100 * score_line_weight
plan_score = school['plan'] * plan_weight
feature_score = 0
if school['feature'] == '艺术生':
feature_score = 10 * feature_weight
elif school['feature'] == '体育生':
feature_score = 5 * feature_weight
total_score = score_line_score + plan_score + feature_score
return total_score
# 根据评分对学校进行排序
def sort_schools(schools):
# 根据评分对学校进行排序
sorted_schools = sorted(schools, key=lambda x: x['score'], reverse=True)
return sorted_schools
# 输出预测结果
def output_result(sorted_schools):
# 输出前 5 个预测结果
print('根据您的考试成绩,您有可能被以下学校录取:')
for i in range(5):
school = sorted_schools[i]
print('{} - {} - {} - {}'.format(school['name'], school['city'], school['score'], school['feature']))
# 用户输入成绩
score = float(input("请输入您的考试分数:"))
# 读取学校信息
schools = read_school_info()
# 计算学校评分
for school in schools:
school['score'] = calculate_score(school, score)
# 根据评分排序
sorted_schools = sort_schools(schools)
# 输出预测结果
output_result(sorted_schools)
```
在这个实现过程中,我们假设学校信息存储在一个文本文件 `schools.txt` 中,每一行包含学校名称、所在城市、录取分数线、招生计划和特色等信息,用逗号进行分割。同时,我们使用加权平均分计算学校评分,根据录取分数线、招生计划和特色三个因素进行评分。最后,我们输出前 5 个预测结果,包括学校名称、所在城市、评分和特色等信息。
阅读全文