Write the following code in c #,2. Write a method that takes an argument (an int array) and print each item on a single line separated by a space. From your main, call this method with numbers as argument.6. In your main method use the method in question 2 to display the numbers array, then use the Array.Binarysearch() method to try to find the position of 3 in the numbers array. What is your answer? Now repeat the same steps after you have sorted the array and printed the sorted array

Sure, here's the code in C#:

using System;

class Program
{
    static void Main(string[] args)
    {
        int[] numbers = { 4, 2, 6, 3, 7, 1 };
        PrintIntArray(numbers);
        int index = Array.BinarySearch(numbers, 3);
        Console.WriteLine("Index of 3: " + index);

        Array.Sort(numbers);
        PrintIntArray(numbers);
        index = Array.BinarySearch(numbers, 3);
        Console.WriteLine("Index of 3: " + index);
    }

    static void PrintIntArray(int[] arr)
    {
        foreach (int i in arr)
        {
            Console.Write(i + " ");
        }
        Console.WriteLine();
    }
}

The output of this program will be:

4 2 6 3 7 1 
Index of 3: -4
1 2 3 4 6 7 
Index of 3: 2

The `PrintIntArray` method takes an int array as an argument and prints out each element separated by a space. In the `Main` method, we first call `PrintIntArray` to display the original `numbers` array. We then use the `Array.BinarySearch` method to try to find the index of 3 in the array, which returns -4 since 3 is not found.

We then sort the `numbers` array using the `Array.Sort` method, and call `PrintIntArray` to display the sorted array. We then use `Array.BinarySearch` again to find the index of 3 in the sorted array, which now returns 2 since 3 is the third element in the sorted array.