matlab编码尖底摆动从动件盘形凸轮轮廓代码

由于尖底摆动从动件盘形凸轮是比较复杂的凸轮形状，没有标准的公式可以计算轮廓，需要通过数值方法来逼近轮廓。以下是一个简单的 MATLAB 代码实现，用来生成尖底摆动从动件盘形凸轮的轮廓：

% 定义凸轮参数
r = 10; % 偏距
a = 20; % 偏心距
b = 30; % 凸轮半径
h = 40; % 凸轮高度
n = 1000; % 绘制点数

% 定义绘制参数
theta = linspace(0, 2*pi, n);
x = zeros(1, n);
y = zeros(1, n);

% 计算凸轮轮廓
for i = 1:n
    % 初始猜测点
    x0 = b*cos(theta(i));
    y0 = b*sin(theta(i));
    % 数值迭代求解
    for j = 1:10
        f = [x0 - (r+a*cos(theta(i)))*cos(atan(y0/(r+a*cos(theta(i)))-a*sin(theta(i))/((r+a*cos(theta(i)))^2)));
             y0 - h*cos(atan(y0/(r+a*cos(theta(i)))-a*sin(theta(i))/((r+a*cos(theta(i)))^2))) - (r+a*cos(theta(i)))*sin(atan(y0/(r+a*cos(theta(i)))-a*sin(theta(i))/((r+a*cos(theta(i)))^2)))];
        J = [-cos(atan(y0/(r+a*cos(theta(i)))-a*sin(theta(i))/((r+a*cos(theta(i)))^2))) + (r+a*cos(theta(i)))*a*cos(theta(i))/((r+a*cos(theta(i)))^2+(y0/(r+a*cos(theta(i))-a*sin(theta(i))))^2), ...
             -1/(1+(y0/(r+a*cos(theta(i))-a*sin(theta(i))))^2)*a/(r+a*cos(theta(i)))*(1/(r+a*cos(theta(i))-a*sin(theta(i))))*sin(theta(i)) - h/(y0^2/(r+a*cos(theta(i))-a*sin(theta(i)))^2+1), ...
             0];
        dx = -J\f;
        x0 = x0 + dx(1);
        y0 = y0 + dx(2);
    end
    x(i) = x0;
    y(i) = y0;
end

% 绘制凸轮轮廓
plot(x, y);
axis equal;

代码中使用了数值迭代方法来求解凸轮轮廓，具体实现过程较为复杂，需要进行多次迭代才能得到较为精确的结果。最终得到的凸轮轮廓是一个由多个点组成的曲线，通过使用 `plot` 函数将其绘制出来。