八数码问题启发式搜索在Ubuntu中怎么运行呢,可以详细的告诉我吗
时间: 2024-06-08 11:09:31 浏览: 53
八数码问题是一种经典的搜索问题,启发式搜索是其中的一种常用解法。在Ubuntu中,你可以使用Python语言编写程序来解决这个问题,并且使用Pygame库来进行图形化展示。
以下是一个简单的示例代码,供你参考:
```python
import pygame
import sys
import time
import copy
# 定义颜色
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)
# 定义游戏界面大小和格子大小
WINDOW_SIZE = [480, 480]
BLOCK_SIZE = 60
# 定义八数码问题的初始状态和目标状态
INIT_STATE = [[0, 1, 3], [4, 2, 5], [7, 8, 6]]
GOAL_STATE = [[1, 2, 3], [4, 5, 6], [7, 8, 0]]
# 定义节点类
class Node:
def __init__(self, state, parent=None, action=None, depth=0):
self.state = state
self.parent = parent
self.action = action
self.depth = depth
self.heuristic = self.calculate_heuristic()
# 计算启发式函数值
def calculate_heuristic(self):
distance = 0
for i in range(3):
for j in range(3):
if self.state[i][j] != GOAL_STATE[i][j]:
row, col = divmod(self.state[i][j], 3)
distance += abs(row - i) + abs(col - j)
return distance
# 获取路径
def get_path(self):
path = []
node = self
while node:
path.append(node)
node = node.parent
return path[::-1]
# 定义搜索算法
def a_star_search(init_state):
# 初始化起始节点
start_node = Node(init_state)
# 初始化开放列表和关闭列表
open_list = [start_node]
closed_list = []
while open_list:
# 从开放列表中选择启发式函数值最小的节点
current_node = min(open_list, key=lambda x: x.heuristic + x.depth)
# 如果当前节点为目标状态,则返回路径
if current_node.state == GOAL_STATE:
return current_node.get_path()
# 将当前节点从开放列表中移除,并添加到关闭列表中
open_list.remove(current_node)
closed_list.append(current_node)
# 生成子节点并加入开放列表中
for action in ["UP", "DOWN", "LEFT", "RIGHT"]:
new_state = get_new_state(current_node.state, action)
if new_state is None:
continue
new_node = Node(new_state, current_node, action, current_node.depth + 1)
if new_node in closed_list:
continue
if new_node in open_list:
index = open_list.index(new_node)
if new_node.depth < open_list[index].depth:
open_list[index] = new_node
else:
open_list.append(new_node)
# 获取新状态
def get_new_state(state, action):
new_state = copy.deepcopy(state)
row, col = get_blank_position(new_state)
if action == "UP":
if row == 0:
return None
new_state[row][col], new_state[row-1][col] = new_state[row-1][col], new_state[row][col]
elif action == "DOWN":
if row == 2:
return None
new_state[row][col], new_state[row+1][col] = new_state[row+1][col], new_state[row][col]
elif action == "LEFT":
if col == 0:
return None
new_state[row][col], new_state[row][col-1] = new_state[row][col-1], new_state[row][col]
elif action == "RIGHT":
if col == 2:
return None
new_state[row][col], new_state[row][col+1] = new_state[row][col+1], new_state[row][col]
return new_state
# 获取空白格的位置
def get_blank_position(state):
for i in range(3):
for j in range(3):
if state[i][j] == 0:
return i, j
# 绘制界面
def draw_board(screen, board):
for i in range(3):
for j in range(3):
rect = pygame.Rect(j*BLOCK_SIZE, i*BLOCK_SIZE, BLOCK_SIZE, BLOCK_SIZE)
pygame.draw.rect(screen, WHITE, rect, 1)
if board[i][j] != 0:
font = pygame.font.Font(None, 36)
text = font.render(str(board[i][j]), True, BLACK)
screen.blit(text, (j*BLOCK_SIZE + BLOCK_SIZE//2 - text.get_width()//2, i*BLOCK_SIZE + BLOCK_SIZE//2 - text.get_height()//2))
# 主函数
def main():
pygame.init()
# 设置窗口标题和大小
pygame.display.set_caption("Eight Puzzle")
screen = pygame.display.set_mode(WINDOW_SIZE)
# 进行搜索
path = a_star_search(INIT_STATE)
# 按路径步骤绘制界面
for node in path:
screen.fill(BLACK)
draw_board(screen, node.state)
pygame.display.flip()
time.sleep(0.5)
# 等待退出
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
if __name__ == "__main__":
main()
```
你可以将上述代码保存在一个.py文件中,然后在终端中使用以下命令运行:
```
python 文件名.py
```
程序将会自动开始搜索并展示结果。
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