使用C语言将下面的字符串中的timestr段和timestamp段给解析出来

假设字符串为str，可以使用正则表达式来解析出timestr段和timestamp段：

#include <regex.h>
#include <stdio.h>
#include <stdlib.h>

int main() {
    char* str = "timestr=2022-01-01 12:00:00&timestamp=1641015600";
    regex_t regex;
    int reti;
    regmatch_t pmatch[2];
    char* timestr;
    char* timestamp;
    
    // 编译正则表达式
    reti = regcomp(&regex, "timestr=([^&]*)", REG_EXTENDED);
    if (reti) {
        fprintf(stderr, "Could not compile regex\n");
        exit(1);
    }
    
    // 匹配timestr段
    reti = regexec(&regex, str, 2, pmatch, 0);
    if (!reti && pmatch[1].rm_so != -1) {
        int len = pmatch[1].rm_eo - pmatch[1].rm_so;
        timestr = (char*)malloc(len + 1);
        strncpy(timestr, str + pmatch[1].rm_so, len);
        timestr[len] = '\0';
        printf("timestr: %s\n", timestr);
    } else {
        fprintf(stderr, "No match for timestr\n");
    }
    
    // 编译正则表达式
    reti = regcomp(&regex, "timestamp=([^&]*)", REG_EXTENDED);
    if (reti) {
        fprintf(stderr, "Could not compile regex\n");
        exit(1);
    }
    
    // 匹配timestamp段
    reti = regexec(&regex, str, 2, pmatch, 0);
    if (!reti && pmatch[1].rm_so != -1) {
        int len = pmatch[1].rm_eo - pmatch[1].rm_so;
        timestamp = (char*)malloc(len + 1);
        strncpy(timestamp, str + pmatch[1].rm_so, len);
        timestamp[len] = '\0';
        printf("timestamp: %s\n", timestamp);
    } else {
        fprintf(stderr, "No match for timestamp\n");
    }
    
    return 0;
}

输出：

timestr: 2022-01-01 12:00:00
timestamp: 1641015600