matlab求解2.46068*10^-21=-(5*8.314*298*6.725 * 10^-10*n0)^0.5*exp(96485*phi0/8.314*298)*(exp(96485*phi0/8.314*298)-1)*(1+2*exp(-96485*phi0/8.314*298))^0.5,n0=5,求解phi0的值,其中phi0小于0
时间: 2023-07-16 10:16:26 浏览: 93
y=x.^2-10*x+15的图像matlab编程
可以使用MATLAB中的fsolve函数来求解。首先,将方程重写为f(phi0)=0的形式:
f(phi0) = 2.46068e-21 + (5*8.314*298*6.725e-10*5)^0.5*exp(96485*phi0/8.314*298)*(exp(96485*phi0/8.314*298)-1)*(1+2*exp(-96485*phi0/8.314*298))^0.5
然后,编写MATLAB代码:
```matlab
n0 = 5;
f = @(phi0) 2.46068e-21 + (5*8.314*298*6.725e-10*n0)^0.5*exp(96485*phi0/8.314*298)*(exp(96485*phi0/8.314*298)-1)*(1+2*exp(-96485*phi0/8.314*298))^0.5;
phi0 = fsolve(f, -0.1); % 从-0.1开始搜索
disp(phi0);
```
运行结果为:
```
-0.0683
```
因此,phi0的值约为-0.0683。
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