我加了STR_TO_DATE函数，但是报错function str_to_date(character varying, unknown) does not exist 建议：No function matches the given name and argument types. You might need to add explicit type casts.

根据错误提示，数据库中似乎不存在名为 `str_to_date` 的函数。这是因为 `str_to_date` 函数是 MySQL 中的函数，在 PostgreSQL 中并不存在。在 PostgreSQL 中可以使用 `to_timestamp` 函数进行字符转日期时间类型的转换。

可以使用类似如下的方式将字符类型的参数转换为时间类型：

to_timestamp(createDate, 'YYYY-MM-DD HH24:MI:SS')

其中，'YYYY-MM-DD HH24:MI:SS' 是表示日期时间格式的字符串，需要根据实际情况进行修改。

需要注意的是，`to_timestamp` 函数返回的是 `timestamp with time zone` 类型的值，如果需要与 `create_date` 字段进行比较，需要使用 `at time zone` 将其转换为相同的时区，例如：

to_timestamp(createDate, 'YYYY-MM-DD HH24:MI:SS') at time zone 'UTC'

这样就可以将返回的时间戳转换为 UTC 时区的时间，然后与 `create_date` 字段进行比较。

相关问题

ERROR: operator does not exist: character varying = integer

This error occurs when you try to compare a string (character varying) with an integer using the equality operator (=) in a SQL query. The equality operator only works between two values of the same data type, so you cannot compare a string with an integer directly.

To resolve this error, you need to make sure that you are comparing values of the same data type. You can use the CAST or CONVERT function to convert one data type to another before comparing them. For example, if you have a string column named "mycolumn" and an integer value 123, you can convert the integer value to a string and compare it with the string column as follows:

SELECT * FROM mytable WHERE mycolumn = CAST(123 AS VARCHAR);

Alternatively, you can convert the string column to an integer and compare it with the integer value:

SELECT * FROM mytable WHERE CAST(mycolumn AS INTEGER) = 123;

Make sure to choose the appropriate data type conversion function based on the data types of the values you are comparing.

"ERROR: operator does not exist: character varying = integer

This error occurs when you try to compare a string (character varying) with an integer using the equal (=) operator. It means that the two data types are not compatible for comparison.

For example, let's say you have a table with a column named "age" of type integer, and you want to filter the results to only show records where the age is equal to a certain value. If you mistakenly write the query like this:

SELECT * FROM my_table WHERE age = '25';

You will get the "ERROR: operator does not exist: character varying = integer" error because you are trying to compare an integer column with a string value ('25').

To fix this error, make sure that you are comparing values of the same data type. In the above example, you should use an integer value instead of a string value:

SELECT * FROM my_table WHERE age = 25;