帮我写一个aps排产算法
时间: 2023-04-10 16:02:59 浏览: 86
好的,我可以为您提供一个基于遗传算法的aps排产算法的代码实现。以下是示例代码:
```python
import random
# 定义工件类
class Job:
def __init__(self, name, duration):
self.name = name
self.duration = duration
# 定义工序类
class Operation:
def __init__(self, job, machine):
self.job = job
self.machine = machine
# 定义机器类
class Machine:
def __init__(self, name):
self.name = name
self.operations = []
def add_operation(self, operation):
self.operations.append(operation)
# 定义遗传算法类
class GeneticAlgorithm:
def __init__(self, jobs, machines, population_size, generations):
self.jobs = jobs
self.machines = machines
self.population_size = population_size
self.generations = generations
def run(self):
population = self.initialize_population()
for i in range(self.generations):
population = self.evolve_population(population)
return self.get_best_schedule(population)
def initialize_population(self):
population = []
for i in range(self.population_size):
schedule = self.create_random_schedule()
population.append(schedule)
return population
def create_random_schedule(self):
schedule = []
for job in self.jobs:
operations = []
for machine in self.machines:
operation = Operation(job, machine)
operations.append(operation)
random.shuffle(operations)
schedule += operations
return schedule
def evolve_population(self, population):
new_population = []
for i in range(self.population_size):
parent1 = self.select_parent(population)
parent2 = self.select_parent(population)
child = self.crossover(parent1, parent2)
child = self.mutate(child)
new_population.append(child)
return new_population
def select_parent(self, population):
tournament_size = 5
tournament = random.sample(population, tournament_size)
tournament.sort(key=lambda x: self.get_fitness(x))
return tournament[0]
def crossover(self, parent1, parent2):
child = parent1[:]
for i in range(len(parent2)):
if random.random() < 0.5:
operation = parent2[i]
if operation not in child:
index = child.index(parent1[i])
child[index] = operation
return child
def mutate(self, schedule):
mutation_rate = 0.1
for i in range(len(schedule)):
if random.random() < mutation_rate:
j = random.randint(0, len(schedule) - 1)
schedule[i], schedule[j] = schedule[j], schedule[i]
return schedule
def get_best_schedule(self, population):
population.sort(key=lambda x: self.get_fitness(x))
return population[0]
def get_fitness(self, schedule):
makespan = self.get_makespan(schedule)
return 1 / makespan
def get_makespan(self, schedule):
machine_times = {}
for machine in self.machines:
machine_times[machine] = 0
for operation in schedule:
job = operation.job
machine = operation.machine
start_time = machine_times[machine]
end_time = start_time + job.duration
machine_times[machine] = end_time
return max(machine_times.values())
# 示例用法
jobs = [Job('A', 3), Job('B', 2), Job('C', 4)]
machines = [Machine('M1'), Machine('M2'), Machine('M3')]
ga = GeneticAlgorithm(jobs, machines, 10, 100)
schedule = ga.run()
print([operation.job.name for operation in schedule])
```
希望这个代码能够帮助您实现aps排产算法。