去掉一个最高分和一个最高分然后取其余3名评委的平均分作为最后得分用c语言

可以使用以下代码实现：

#include <stdio.h>

int main() {
int scores[5]; // 存储5个评委的分数
int sum = ; // 存储总分
int max1 = , max2 = ; // 存储最高分和次高分

// 输入5个评委的分数
for (int i = ; i < 5; i++) {
printf("请输入第%d个评委的分数：", i+1);
scanf("%d", &scores[i]);

// 更新最高分和次高分
if (scores[i] > max1) {
max2 = max1;
max1 = scores[i];
} else if (scores[i] > max2) {
max2 = scores[i];
}

// 累加总分
sum += scores[i];
}

// 计算最终得分
int final_score = (sum - max1 - max2) / 3;

printf("最终得分为：%d\n", final_score);

return ;
}

相关问题

用c语言写一个五个评委为参赛选手打分，选手最后得分要去掉一个最高分，去掉一个最低分，然后求平均分作为选手成绩。不用数组

您好！感谢您使用 ChitGPT 进行对话。根据您的需求，我可以提供以下 C 语言代码，实现对五个评委为参赛选手打分，选手最后得分要去掉一个最高分，去掉一个最低分，然后求平均分作为选手成绩的功能，但不使用数组：

#include <stdio.h>
#include <limits.h>

int main() {
    int judge1, judge2, judge3, judge4, judge5;
    int highest, lowest, sum, avg;
    sum = 0;
    highest = INT_MIN; /* initialize as smallest value */
    lowest = INT_MAX; /* initialize as largest value */

    /* read in scores from the judges */
    printf("Enter score from judge 1: ");
    scanf("%d", &judge1);
    printf("Enter score from judge 2: ");
    scanf("%d", &judge2);
    printf("Enter score from judge 3: ");
    scanf("%d", &judge3);
    printf("Enter score from judge 4: ");
    scanf("%d", &judge4);
    printf("Enter score from judge 5: ");
    scanf("%d", &judge5);

    /* find the highest and lowest scores */
    if (judge1 > highest) {
        highest = judge1;
    }
    if (judge1 < lowest) {
        lowest = judge1;
    }
    if (judge2 > highest) {
        highest = judge2;
    }
    if (judge2 < lowest) {
        lowest = judge2;
    }
    if (judge3 > highest) {
        highest = judge3;
    }
    if (judge3 < lowest) {
        lowest = judge3;
    }
    if (judge4 > highest) {
        highest = judge4;
    }
    if (judge4 < lowest) {
        lowest = judge4;
    }
    if (judge5 > highest) {
        highest = judge5;
    }
    if (judge5 < lowest) {
        lowest = judge5;
    }

    /* calculate the sum of the scores */
    sum = judge1 + judge2 + judge3 + judge4 + judge5 - highest - lowest;

    /* calculate the average score */
    avg = sum / 3;

    /* print out the final score */
    printf("Final score: %d\n", avg);

    return 0;
}

希望这个代码能够满足您的需求。如果还有其他需要，请随时问我。

用C语言输入n个评委的打分，计算并输出参赛选手的最后得分。计算方法为去除一个最高分和去除一个最低分，其余的进行平均，得出参赛选手的最后得分

下面是C语言的代码实现：

#include <stdio.h>

#define MAX_JUDGE_NUM 10 // 最多的评委人数

int main() {
    int n; // 评委人数
    int scores[MAX_JUDGE_NUM]; // 评委们的打分
    int max_score = -1, min_score = 101; // 最高分和最低分
    int sum_score = 0; // 所有评委的总分数

    printf("请输入评委的人数（不超过%d个）：", MAX_JUDGE_NUM);
    scanf("%d", &n);

    // 读入每个评委的打分
    for (int i = 0; i < n; i++) {
        printf("请输入第%d个评委的打分：", i + 1);
        scanf("%d", &scores[i]);

        // 更新最高分和最低分
        if (scores[i] > max_score) {
            max_score = scores[i];
        }
        if (scores[i] < min_score) {
            min_score = scores[i];
        }

        sum_score += scores[i]; // 累加总分数
    }

    // 去掉一个最高分和一个最低分
    sum_score -= max_score;
    sum_score -= min_score;

    // 计算最终得分并输出
    double final_score = sum_score * 1.0 / (n - 2);
    printf("参赛选手的最终得分为：%.2f\n", final_score);

    return 0;
}

程序的核心思路是读入每个评委的打分，同时记录下最高分和最低分，累加总分数。然后去掉一个最高分和一个最低分，计算最终得分并输出。需要注意的是，最终得分要用 `double` 类型存储，否则可能会丢失精度。