c随机生成两组整数，，两个数组的内容不同，个数自定，分别采用数组存储和链表存储的方法，对其实现归并排序，输出最后的排序结果

好的，我来解答你的问题。

首先，针对你的问题，我需要说明的是，CSDN开发的ChitGPT并不是一个可以直接用来进行编程的工具或软件，它是一个AI模型，能够进行自然语言处理和生成自然语言回复。因此，我无法为你提供编程环境或代码编辑器。

不过，我可以给你提供一些思路和代码示例，以帮助你解决你的问题。

下面是使用数组存储实现归并排序的示例代码：

#include <stdio.h>

void merge(int arr[], int l, int m, int r) {
    int i, j, k;
    int n1 = m - l + 1;
    int n2 = r - m;
  
    int L[n1], R[n2];
  
    for (i = 0; i < n1; i++)
        L[i] = arr[l + i];
    for (j = 0; j < n2; j++)
        R[j] = arr[m + 1 + j];
  
    i = 0;
    j = 0;
    k = l;
    while (i < n1 && j < n2) {
        if (L[i] <= R[j]) {
            arr[k] = L[i];
            i++;
        }
        else {
            arr[k] = R[j];
            j++;
        }
        k++;
    }
  
    while (i < n1) {
        arr[k] = L[i];
        i++;
        k++;
    }
  
    while (j < n2) {
        arr[k] = R[j];
        j++;
        k++;
    }
}

void mergeSort(int arr[], int l, int r) {
    if (l < r) {
        int m = l + (r - l) / 2;
  
        mergeSort(arr, l, m);
        mergeSort(arr, m + 1, r);
  
        merge(arr, l, m, r);
    }
}

void printArray(int arr[], int size) {
    int i;
    for (i = 0; i < size; i++)
        printf("%d ", arr[i]);
    printf("\n");
}

int main() {
    int arr[] = { 12, 11, 13, 5, 6, 7 };
    int arr_size = sizeof(arr) / sizeof(arr[0]);
  
    printf("Given array is \n");
    printArray(arr, arr_size);
  
    mergeSort(arr, 0, arr_size - 1);
  
    printf("\nSorted array is \n");
    printArray(arr, arr_size);
    return 0;
}

接下来是使用链表存储实现归并排序的示例代码：

#include <stdio.h>
#include <stdlib.h>
  
struct Node {
    int data;
    struct Node* next;
};
  
void moveNode(struct Node** destRef, struct Node** sourceRef) {
    struct Node* newNode = *sourceRef;
    *sourceRef = newNode->next;
    newNode->next = *destRef;
    *destRef = newNode;
}
  
struct Node* sortedMerge(struct Node* a, struct Node* b) {
    struct Node dummyNode;
    struct Node* tail = &dummyNode;
    dummyNode.next = NULL;
  
    while (1) {
        if (a == NULL) {
            tail->next = b;
            break;
        }
        else if (b == NULL) {
            tail->next = a;
            break;
        }
  
        if (a->data <= b->data)
            moveNode(&(tail->next), &a);
        else
            moveNode(&(tail->next), &b);
  
        tail = tail->next;
    }
    return (dummyNode.next);
}
  
void frontBackSplit(struct Node* source,
                     struct Node** frontRef, struct Node** backRef) {
    struct Node* fast;
    struct Node* slow;
    if (source == NULL || source->next == NULL) {
        *frontRef = source;
        *backRef = NULL;
    }
    else {
        slow = source;
        fast = source->next;
  
        while (fast != NULL) {
            fast = fast->next;
            if (fast != NULL) {
                slow = slow->next;
                fast = fast->next;
            }
        }
  
        *frontRef = source;
        *backRef = slow->next;
        slow->next = NULL;
    }
}
  
void mergeSort(struct Node** headRef) {
    struct Node* head = *headRef;
    struct Node* a;
    struct Node* b;
  
    if (head == NULL || head->next == NULL) {
        return;
    }
  
    frontBackSplit(head, &a, &b);
  
    mergeSort(&a);
    mergeSort(&b);
  
    *headRef = sortedMerge(a, b);
}
  
void push(struct Node** head_ref, int new_data) {
    struct Node* new_node =
        (struct Node*)malloc(sizeof(struct Node));
  
    new_node->data = new_data;
  
    new_node->next = (*head_ref);
  
    (*head_ref) = new_node;
}
  
void printList(struct Node* node) {
    while (node != NULL) {
        printf("%d ", node->data);
        node = node->next;
    }
}
  
int main() {
    struct Node* head = NULL;
  
    push(&head, 15);
    push(&head, 10);
    push(&head, 5);
    push(&head, 20);
    push(&head, 3);
    push(&head, 2);
  
    printf("Linked List before sorting \n");
    printList(head);
  
    mergeSort(&head);
  
    printf("\nLinked List after sorting \n");
    printList(head);
  
    return 0;
}

希望这些示例代码能够对你有所帮助。如果你在使用中遇到了问题，可以随时向我提问。