C#获取yaml文件中父节点buildRelease下所有子节点为releaseID的值以及子节点buildEnvironment下的所有子节点为buildSystem的值

在C#中，要从YAML文件中获取特定结构的数据，你可以使用`System.IO.Parsing.YamlParser`或第三方库如`YamlDotNet`。假设我们有一个简单的YAML格式，其中包含你描述的结构：

builds:
  buildRelease:
    - releaseID: value1
      buildEnvironment:
        buildSystem: system1
    - releaseID: value2
      buildEnvironment:
        buildSystem: system2

  # ...更多buildRelease节点...

首先，你需要安装相关的YAML解析库，比如`YamlDotNet`:

Install-Package YamlDotNet

然后，你可以使用下面的代码片段来读取并提取数据：

using System;
using System.IO;
using YamlDotNet.Reading;

public static class YamlReaderExample
{
    public static void Main()
    {
        string yamlPath = "path_to_your_yaml_file.yaml";

        var parser = new YamlParser();
        var content = File.ReadAllText(yamlPath);
        var deserializedData = parser.Parse(content);

        dynamic builds = deserializedData.builds; // 假设根键名为"builds"

        foreach (var item in builds.buildRelease)
        {
            string releaseID = item.releaseID;
            string buildSystem = ((dynamic)item.buildEnvironment).buildSystem;

            Console.WriteLine($"releaseID: {releaseID}, buildSystem: {buildSystem}");
        }
    }
}

在这个例子中，我们动态地遍历了`buildRelease`数组，并对每个元素的`releaseID`和`buildEnvironment.buildSystem`进行了访问。