用c语言代码实现万年历查询程序 功能要求： （1）提供菜单方式选择 （2）输入年份、月份、日期，计算得到的是这一天据今天有多少天，星期几； （3）输入公历的年月日，输出农历年月日；

好的，我知道您提出的要求，并将为您提供回答。下面是实现万年历查询程序的C语言代码。

#include <stdio.h>

// 声明函数
void menu();
int is_leap_year(int year);
int get_day_of_year(int year, int month, int day);
int get_weekday(int year, int month, int day);
int get_year_days(int year);
void get_lunar_date(int year, int month, int day);
int get_year_days(int year);
int get_lunar_month_days(int year, int month);
void get_lunar_month_day(int year, int month, int day);

int main() {
    int year, month, day;
    int choice;

    while (1) {
        menu();
        printf("请输入您的选择：");
        scanf("%d", &choice);

        switch (choice) {
            case 1:
                printf("请输入年份：");
                scanf("%d", &year);
                printf("请输入月份：");
                scanf("%d", &month);
                printf("请输入日期：");
                scanf("%d", &day);

                int day_of_year = get_day_of_year(year, month, day);
                int weekday = get_weekday(year, month, day);

                printf("这一天据今天有 %d 天\n", day_of_year);
                printf("星期 %d\n", weekday);

                break;
            case 2:
                printf("请输入公历的年月日，例如：2022 3 3\n");
                scanf("%d %d %d", &year, &month, &day);

                printf("公历 %d 年 %d 月 %d 日对应的农历日期为：", year, month, day);
                get_lunar_date(year, month, day);
                printf("\n");

                break;
            case 3:
                printf("感谢您使用本程序，再见！\n");
                return 0;
            default:
                printf("无效的选项，请重新输入！\n");
                break;
        }
    }
}

// 输出菜单
void menu() {
    printf("\n===== 万年历查询程序 =====\n");
    printf("1. 查询这一天据今天有多少天，星期几\n");
    printf("2. 查询公历日期对应的农历日期\n");
    printf("3. 退出程序\n");
}

// 判断是否是闰年
int is_leap_year(int year) {
    if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) {
        return 1;
    } else {
        return 0;
    }
}

// 获取当天是这一年的第几天
int get_day_of_year(int year, int month, int day) {
    int days = 0;

    for (int i = 1; i < month; i++) {
        switch (i) {
            case 1:
            case 3:
            case 5:
            case 7:
            case 8:
            case 10:
            case 12:
                days += 31;
                break;
            case 4:
            case 6:
            case 9:
            case 11:
                days += 30;
                break;
            case 2:
                if (is_leap_year(year)) {
                    days += 29;
                } else {
                    days += 28;
                }
                break;
        }
    }

    days += day;

    return days;
}

// 获取该天是星期几
int get_weekday(int year, int month, int day) {
    int k = year % 100;
    int j = year / 100;
    int q = day;
    int m = month;
    int h = (q + 26 * (m + 1) / 10 + k + k / 4 + j / 4 + 5 * j) % 7;

    return (h + 6) % 7 + 1;
}

// 获取该年共有多少天
int get_year_days(int year) {
    int days = 0;

    for (int i = 1; i <= 12; i++) {
        switch (i) {
            case 1:
            case 3:
            case 5:
            case 7:
            case 8:
            case 10:
            case 12:
                days += 31;
                break;
            case 4:
            case 6:
            case 9:
            case 11:
                days += 30;
                break;
            case 2:
                if (is_leap_year(year)) {
                    days += 29;
                } else {
                    days += 28;
                }
                break;
        }
    }

    return days;
}

// 获取农历日期
void get_lunar_date(int year, int month, int day) {
    int days = 0;
    int lunar_year = year;
    int lunar_month = 1;
    int lunar_day = 1;

    while (1) {
        days += get_year_days(lunar_year);

        if (days > get_day_of_year(year, month, day)) {
            days -= get_year_days(lunar_year);
            break;
        }

        lunar_year++;
    }

    for (int i = 1; i <= 12; i++) {
        int days_of_month = get_lunar_month_days(lunar_year, i);

        if (days >= days_of_month) {
            days -= days_of_month;
            lunar_month++;
        } else {
            break;
        }
    }

    lunar_day += days;
    get_lunar_month_day(lunar_year, lunar_month, lunar_day);
}

// 获取农历年份中该月有多少天
int get_lunar_month_days(int year, int month) {
    int month_day = 29;

    if ((year & 0x03) == 0 && month == 2) {
        month_day = 30;
    } else if ((year & 0x03) != 0 && month == 3) {
        month_day = 30;
    }

    if ((0x8000 >> (month - 1)) & 0x0f) {
        month_day++;
    }

    return month_day;
}

// 获取农历年月日
void get_lunar_month_day(int year, int month, int day) {
    char *g_month[] = {"*","正","二","三","四","五","六","七","八","九","十","冬","腊"};
    char *g_day[] = {"*","初一","初二","初三","初四","初五","初六","初七","初八","初九","初十","十一","十二","十三","十四","十五","十六","十七","十八","十九","二十","廿一","廿二","廿三","廿四","廿五","廿六","廿七","廿八","廿九","三十"};
    char *zodiac[] = {"猴","鸡","狗","猪","鼠","牛","虎","兔","龙","蛇","马","羊"};

    printf("%s年", zodiac[(year - 4) % 12]);
    printf("%s月", g_month[month]);
    printf("%s", g_day[day]);
}

以上就是实现万年历查询程序的C语言代码，您可以根据需要对代码进行适当的修改和调整。希望能够帮到您！