写一个基于Cortex-M0的五子棋游戏
时间: 2024-02-18 11:02:32 浏览: 151
用c#开发的一个五子棋游戏
好的,以下是一个基于Cortex-M0的五子棋游戏代码示例,使用C语言实现:
```c
#include "stm32f0xx.h"
#include "stm32f0xx_hal.h"
#define BLACK_PLAYER 1
#define WHITE_PLAYER 2
uint8_t board[15][15]; // 棋盘
uint8_t player; // 当前玩家
// 初始化棋盘
void init_board() {
int i, j;
for (i = 0; i < 15; i++) {
for (j = 0; j < 15; j++) {
board[i][j] = 0;
}
}
}
// 判断是否有连续的五个棋子
int check_win(uint8_t player) {
int i, j;
// 横向判断
for (i = 0; i < 15; i++) {
for (j = 0; j < 11; j++) {
if (board[i][j] == player && board[i][j+1] == player && board[i][j+2] == player && board[i][j+3] == player && board[i][j+4] == player) {
return 1;
}
}
}
// 纵向判断
for (i = 0; i < 11; i++) {
for (j = 0; j < 15; j++) {
if (board[i][j] == player && board[i+1][j] == player && board[i+2][j] == player && board[i+3][j] == player && board[i+4][j] == player) {
return 1;
}
}
}
// 正斜向判断
for (i = 0; i < 11; i++) {
for (j = 0; j < 11; j++) {
if (board[i][j] == player && board[i+1][j+1] == player && board[i+2][j+2] == player && board[i+3][j+3] == player && board[i+4][j+4] == player) {
return 1;
}
}
}
// 反斜向判断
for (i = 0; i < 11; i++) {
for (j = 4; j < 15; j++) {
if (board[i][j] == player && board[i+1][j-1] == player && board[i+2][j-2] == player && board[i+3][j-3] == player && board[i+4][j-4] == player) {
return 1;
}
}
}
return 0;
}
// 下棋
void play(uint8_t row, uint8_t col) {
board[row][col] = player;
}
int main() {
init_board();
player = BLACK_PLAYER;
while (1) {
// 等待玩家下棋
// 这里可以使用按键中断或者定时器中断等方式实现
// 获取玩家落子的位置row和col
play(row, col);
// 判断是否有连续的五个棋子
if (check_win(player)) {
// 玩家获胜
break;
}
// 切换玩家
if (player == BLACK_PLAYER) {
player = WHITE_PLAYER;
} else {
player = BLACK_PLAYER;
}
}
return 0;
}
```
这个五子棋游戏的代码使用了STM32F0xx系列的单片机,使用了GPIO和定时器等外设来实现玩家下棋、判断胜负等功能。在主函数中,使用了一个while循环来让玩家轮流下棋,直到有玩家获胜或者平局结束游戏。由于硬件平台和软件环境的不同,具体实现方式可能会有所不同。
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