用Xilinx的VHDL语言写出一个基于布斯法的8*8补码乘法器的代码

以下是一个基于布斯法的8*8补码乘法器的VHDL代码实现：

library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.NUMERIC_STD.ALL;

entity Booth_Multiplication is
    Port ( A : in  signed(7 downto 0);
           B : in  signed(7 downto 0);
           CLK : in  STD_LOGIC;
           RST : in  STD_LOGIC;
           P : out  signed(15 downto 0));
end Booth_Multiplication;

architecture Behavioral of Booth_Multiplication is

signal A_reg, B_reg : signed(7 downto 0);
signal P_reg : signed(15 downto 0);
signal C : std_logic;
signal Q : signed(8 downto 0);

begin

process(CLK, RST)
begin
    if (RST='1') then
        A_reg <= (others => '0');
        B_reg <= (others => '0');
        P_reg <= (others => '0');
        Q <= (others => '0');
        C <= '0';

    elsif (rising_edge(CLK)) then
        A_reg <= A;
        B_reg <= B;

        if (Q(0)='0' and C='0') then
            Q <= Q(7 downto 0) & A_reg(0);
            P_reg <= P_reg;
        elsif (Q(0)='1' and C='0') then
            P_reg <= P_reg + (B_reg & "00000001");
            Q <= Q(7 downto 0) & A_reg(0);
        elsif (Q(0)='0' and C='1') then
            P_reg <= P_reg + (B_reg & "11111111");
            Q <= Q(7 downto 0) & A_reg(0);
        elsif (Q(0)='1' and C='1') then
            Q <= Q(7 downto 0) & A_reg(0);
            P_reg <= P_reg + (B_reg & "11111110");
        end if;

        C <= Q(0);
    end if;
end process;

P <= P_reg;

end Behavioral;

该代码实现了一个带有清零复位的 Booth 乘法器，可以在 FPGA 上进行实现并进行功能验证。